The concentration of the drug stock solution is 1.5*10^-9 M i.e. 1.5 * 10^-9 moles of the drug per Liter of the solution
Therefore, the number of moles present in 1 ml i.e. 1*10^-3 L of the solution would be = 1 *10^-3 L * 1.5 * 10^-9 moles/1 L = 1.5 * 10^-12 moles
1 mole of the drug will contain 6.023*10^23 drug molecules
Therefore, 1.5*10^-12 moles of the drug will correspond to :
1.5 * 10^-12 moles * 6.023*10^23 molecules/1 mole = 9.035 * 10^11 molecules
The number of cancer cells = 2.0 * 10^5
Hence the ratio = drug molecules/cancer cells
= 9.035 *10^11/2.0 *10^5
= 4.5 * 10^6
Answer:
1s22s22p3.
Explanation:
Electronic configuration of a neutral atom is 1s22s22p3.
Please see the image attached
Neutral atom of nitrogen will have equal number of proton and electron i.e equal to 7. 7 electron of the nitrogen are placed into the s and p orbitals in the ground state.
Answer:
6 valence electrons
Explanation:
The atom you have given is a sulfur atom. It has 6 valence electrons.
Answer:
Calculate the mass of BR -79? Bromine has 2 naturally occurring isotopes (Br-79 and Br-81) and has an atomic mass of 79.904 amu
Explanation:
if i get this wrong srry
