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3 years ago

Can someone pls pls pls help

Mathematics

1 answer:

vichka [17]3 years ago

4 0

Answer:

4 $\sqrt{3}$

Step-by-step explanation:

AB = $\sqrt{[(4-(-4)]^{2} - [1-(-3)]^{2} }$ = 4 $\sqrt{3}$

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Brooke multiplied 3 and 9 and got 17. Brooke knows her answer is wrong because she knows is should be approximately

34kurt

Answer: 3 times 9 is 27

Step-by-step explanation:

8 0

3 years ago

A regular polygon has an interior angle of 171 degrees. Show your work. (3 points for work, 3 points

gulaghasi [49]

Answer:

a) 40 sides

b) 6840

c) 9 gegrees

Step-by-step explanation:

interior angle= (n-2)180

$(n - 2)180 \div n = 171 \\ 180n - 360 = 171n \\ 180n - 171n = 360 \\ 9n = 360 \\ n = 360 \div 9 = 40 \\$

so total number of sides is 40

b) Sum of interior angles= (n-2)×180

(40-2)×180

38×180

6840

c) Exterior angle = 360 ÷ n

360÷40 =9 degree

7 0

3 years ago

How would you write the following expression as a single term? 3[2 ln(x-1) - lnx] + ln (x+1)

Elan Coil [88]

Apply the rule: $n ln x = ln x^{n}$

$3[2 ln(x-1) - lnx] + ln(x+1)=3[ln(x-1)^{2} - lnx ] + ln(x+1)$

Apply the rule : $log a - log b = log \frac{a}{b}$

$3[2 ln(x-1) - lnx] + ln(x+1)=3ln\frac{(x-1)^{2} }{x} + ln(x+1)$

Apply the rule: $n ln x = ln x^{n}$

$3[ln (x-1)^{2} -ln x]+ln (x+1)= ln \frac{(x-1)^{6} }{x^{3} } +log(x+1)$

Finally, apply the rule: log a + log b = log ab

$3[ln(x-1)^{2} -ln x]+log(x+1)=ln\frac{(x-1)^{6}(x+1) }{x^{3} }$

3 0

4 years ago

How do you find the answer to part a and what is the answer?

dimaraw [331]

Whitch one is part a

4 0

4 years ago

What is the y-coordinate of the solution of the system of equations? {y=3x−262x−y=19 Enter your answer in the box.

Yuki888 [10]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}y=3x-26&(1)\\2x-y=19&(2)\end{array}\right\\\\\text{Substitute (1) to (2):}\\\\2x-(3x-26)=19\\2x-3x+26=19\qquad\text{subtract 26 from both sides}\\-x=-7\qquad\text{change the signs}\\x=7\\\\\text{Put the value of x to (1):}\\\\y=3(7)-26=21-26=-5$

5 0

3 years ago

Can someone pls pls pls help ​

Can someone pls pls pls help