Ba(OH)2 can be neutralized by adding an acid to the solution. We can add HCl to produce:
Ba(OH)2 + 2HCl ===> BaCl2 + 2H2O ; producing a salt BaCl2 and water.
or we can add H2SO4 to produce:
Ba(OH)2 + H2SO4 ===> BaSO4 + 2H2O; producing a salt, BaSO4, and water. <span />
The average rate of reaction over a given interval can be calculated by taking the difference of concentration on a particular given reactant, and dividing it by the total time. In this case, (1.00 M - 0.655 M)/30 s = 0.0115 M/s, or 0.0115 mol/L-s, and this is the final rate of reaction.
Answer:
C8H17N
Explanation:
Mass of the unknown compound = 5.024 mg
Mass of CO2 = 13.90 mg
Mass of H2O = 6.048 mg
Next, we shall determine the mass of carbon, hydrogen and nitrogen present in the compound. This is illustrated below:
For carbon, C:
Molar mass of CO2 = 12 + (2x16) = 44g/mol
Mass of C = 12/44 x 13.90 = 3.791 mg
For hydrogen, H:
Molar mass of H2O = (2x1) + 16 = 18g/mol
Mass of H = 2/18 x 6.048 = 0.672 mg
For nitrogen, N:
Mass N = mass of unknown – (mass of C + mass of H)
Mass of N = 5.024 – (3.791 + 0.672)
Mass of N = 0.561 mg
Now, we can obtain the empirical formula for the compound as follow:
C = 3.791 mg
H = 0.672 mg
N = 0.561 mg
Divide each by their molar mass
C = 3.791 / 12 = 0.316
H = 0.672 / 1 = 0.672
N = 0.561 / 14 = 0.040
Divide by the smallest
C = 0.316 / 0.04 = 8
H = 0.672 / 0.04 = 17
N = 0.040 / 0.04 = 1
Therefore, the empirical formula for the compound is C8H17N
Answer:
Two water molecules contain 4 hydrogen atoms and 2 oxygen atoms. A mole of water molecules contains 2 moles of hydrogen atoms and 1 mole of oxygen atoms.
Explanation:
Answer:
a) If the solvent-solute interactions in a mixture are <u>stronger than</u> the solvent-solvent interactions and the solute-solute interactions, a homogeneous solution forms.
b) If the solvent-solute interactions in a mixture are <u>weaker than</u> the solvent-solvent interactions and the solute-solute interactions, the formation of a homogeneous solution is uncertain.
Explanation:
The solubility of solute in given solvent mainly depends upon the intermolecular interactions between the solvent and the solute. If the solute is surrounded and solvated by the solvent then the solute will dissolve in that solvent. Therefore, in order to dissolve the solute must form stronger interactions with the solvent as compared to the solute solute interactions or solvent solvent interactions.
Example:
When NaCl is added to water the partial negative oxygen of water is attracted to Na⁺ of NaCl and the partial positive hydrogen of water is attracted to Cl⁻ of NaCl. These new interactions between the NaCl ions and water are stronger than the interactions between water molecules and NaCl molecules themselves hence, results in solubility of NaCl in water.
On the other hand, if NaCl is added to Hexane (C₆H₁₄) it fails to make strong interactions with the solvent molecules resulting in insolubility of NaCl in hexane.
