Classify each of these compounds as a Brønsted-Lowry acid, a Brønsted-Lowry base, or neither.

Where did the molecules of carbon dioxide come from while the tortilla chip was burning

CaHeK987 [17]

The answer can be explained when you burn something cleanly (with a very hot item) or not. With a candle lots of Carbon dioxide is producted but when using a bunson burner hardly any CO2 is produced.

5 0

3 years ago

The compound known as diethyl ether, commonly referred to as ether, contains carbon, hydrogen, and oxygen. A 1.376 g sample of e

hoa [83]

Answer:

The answer to your question is: C₄H₁₀O

Explanation:

Data

CxHyOz

mass sample : 1.376 g

mass CO₂ = 3.268 g

mass H₂O = 1.672 g

Process

Reaction

CxHyOz + O₂ ⇒ CO₂ + H₂O

1.- Calculate the moles and mass of carbon

Molecular mass CO₂ = 44g

44 g of CO₂ -------------- 12 g of C

3.268 g of CO₂ -------- x

x = (3.268 x 12) / 44

x = 0.891 g of Carbon

12 g of carbon ----------- 1 mol

0.891 g of C ---------- x

x = (0.891 x 1) / 12

x = 0.0743 moles of carbon

2.- Calculate the moles and mass of hydrogen

18 g of water --------------- 2 g of H

1.672 g of H₂O ------------ x

x = (1.672 x 2) / 18

x = 0.186 g of hydrogen

1 g of hydrogen ------------ 1 mol of H

0.186 g of H ------------ x

x = (0.186 x 1) / 1

x = 0.186 moles of H

3.- Calculate the mass of Oxygen and its moles

Mass of Oxygen = 1.376 - 0.891 - 0.186

= 0.299 g of O₂

Moles of Oxygen

16 g of Oxygen ---------------- 1 mol

0.299 g of O ----------------- x

x = (0.299 x 1) / 16

x = 0.019 moles of Oxygen

4.- Divide by the lowest number of moles

Carbon 0.0743/ 0.019 = 3.9 ≈ 4.0

Hydrogen 0.186/ 0.019 = 9.7 = 10

Oxygen 0.019/ 0.019 = 1

5.- Write the empirical formula

C₄H₁₀O

4 0

3 years ago

1.86 g H2 is allowed to react with 9.75 g N2 , producing 2.87g NH3.

svet-max [94.6K]

Answer:

(a) Theoretical Yield = 10.50 g

(b) %age yield = 27.33 %

Explanation:

Answer-Part-(a)

The balance chemical equation for the synthesis of Ammonia is as follow;

N₂ + 3 H₂ → 2 NH₃

Step 1: Calculating moles of N₂ as;

Moles = Mass / M/Mass

Moles = 9.75 g / 28.01 g/mol

Moles = 0.348 moles of N₂

Step 2: Calculating moles of H₂ as;

Moles = Mass / M/Mass

Moles = 1.86 g / 2.01 g/mol

Moles = 0.925 moles

Step 3: Finding Limiting reagent as;

According to equation,

1 mole of N₂ reacts with = 3 moles of H₂

So,

0.348 moles of N₂ will react with = X moles of H₂

Solving for X,

X = 3 mol × 0.348 mol / 1 mol

X = 1.044 mol of H₂

It shows that to consume 0.348 moles of N₂ completely we require 1.044 mol of Hydrogen while, as given in statement we are only provided with 0.925 moles of H₂ hence, hydrogen is limiting reagent. Therefore, H₂ will control the final yield.

Step 4: Calculating moles of Ammonia as,

According to equation,

3 mole of H₂ produces = 2 moles of NH₃

So,

0.925 moles of H₂ will produce = X moles of NH₃

Solving for X,

X = 2 mol × 0.925 mol / 3 mol

X = 0.616 mol of NH₃

Step 5: Calculating theoretical yield of Ammonia as,

Theoretical Yield = Moles × M.Mass

Theoretical Yield = 0.616 mol × 17.03 g/mol

Theoretical Yield = 10.50 g

Answer-Part-(b)

%age yield = Actual Yield / Theoretical Yield × 100

%age yield = 2.87 g / 10.50 g × 100

%age yield = 27.33 %

4 0

3 years ago

Consider the following reaction at 298K.

lakkis [162]

The true statements are;

K < 0
Eocel < 0

<h3>What is a redox reaction?</h3>

We define a redox reaction as one in which a specie is oxidized and another is reduced.

Now;

Eo cell = cell potential = -0.13 V - (+0.34 V) = -0.47 V

n =number of moles of electrons = 2 mole of electrons

K = equilibrium constant

ΔG = change in free energy

Eo cell = 0.0592/n log K

-0.47 = 0.0592/2 log K

log K = -0.47 * 2/0.0592

K = 1.3 * 10^-16

ΔG = -nFEo cell

ΔG = -(2 * 96500 * -0.47)

ΔG = 90.7kJ

Learn more about Ecell:brainly.com/question/10203847

#SPJ1

8 0

2 years ago

Which type of force occurs between two objects at a distance?

agasfer [191]

Answer:

Gravitational force of attraction.

Explanation:

When two bodies of masses 'm' and 'M' are separated by a distance 'r', then both the bodies experience a force of attraction towards each other. This force of attraction is called gravitational force. It is a weak force but it always act between two bodies that have mass.

The magnitude of the gravitational force is directly proportional to product of the masses and inversely proportional to the square of the distance between the masses.

This means that as the distance between the bodies is increases, the gravitational force between the bodies decreases and vice versa.

The gravitational force of attraction is given as:

$F_g=\frac{GmM}{r^2}\\\\G\to \textrm{Universal Gravitational constant}$

5 0

3 years ago