All categories

3 years ago

Periodic table puzzles

Chemistry

1 answer:

Zielflug [23.3K]3 years ago

4 0

Answer:

Explanation:

I can explain if you ask

You might be interested in

6. Who stated that matter is not composed of particles

Elena L [17]

After careful consideration your answer is...

Leucippus and Democritus

*Hope I helped*

~Alanna~

8 0

3 years ago

Read 2 more answers

A mixture of H2 and water vapor is present in a closed vessel at 20°C. The total pressure of the system is 755.0 mmHg.

sukhopar [10]

Answer:

737.5mmHg

Explanation:

7 0

4 years ago

Which term describes this reaction? upper c upper h subscript 3 upper b r (a q) plus upper o upper h superscript minus (a q) rig

Veronika [31]

The reaction is a substitution reaction since bromide ion was replaced by hydroxide ion.

<h3>What is a chemical reaction?</h3>

A chemical reaction is a change which results in a the permanent rearrangements of the atoms and constituents of a substance such that new substances are formed.

The given reaction is a as follows:

$CH_3Br (aq) + OH^{-} (aq) \rightarrow CH_3OH (aq) + Br^{-} (aq) \\$

Bromide ion was replaced by hydroxide ion.

Therefore, the reaction is a substitution reaction.

Learn more about chemical reactions at: brainly.com/question/16416932

6 0

2 years ago

Write a balanced equation for the following:

Ket [755]

(ANS1)— P4 + 5O2 ---> 2P2O5

(ANS2)— C3H8 + 5O2---> 3CO2 + 4H20

(ANS3)— Ca2Si + 4Cl2 ---> 2CaCl2 + SiCl4

7 0

3 years ago

If you complete and balance the following oxidation-reduction reaction in basic solution NO2−(aq) + Al(s) → NH3(aq) + Al(OH)4−(a

andreev551 [17]

Answer:

NO2- + 5H2O + 2Al + OH- → NH3 + 2Al(OH)4-

There is 1 hydroxide ion, on the reactant side

Explanation:

NO2−(aq) + Al(s) → NH3(aq) + Al(OH)4−(aq)

Step 1: The half reactions

NO2- (aq) → NH3(g)

Al(s) → Al(OH)4-

<u>Step 2: </u>Balancing electrons

NO2- → NH3

On the left side N has an oxidation number of +3 and on the right side -3.

NO2- +6e-→ NH3

Al(s) → Al(OH)4-

On the left side, Al has an oxidation number of 0 and on the right side +3.

Al(s) → Al(OH)4- +3e-

To have the same amount of electrons transfered, we have to multiply the second reaction by 2

NO2- +6e-→ NH3

2(Al(s) → Al(OH)4- +6e-)

<u>Step 3:</u> Balance with OH/H2O

NO2- +6e +5H2O → NH3 +7OH-

2Al +8OH- → 2Al(OH)4- + 6e-

<u>Step 4:</u> The netto reaction

NO2- + 5H2O + 2Al + 8OH- → NH3 +7OH- + 2Al(OH)4-

NO2- + 5H2O + 2Al + OH- → NH3 + 2Al(OH)4-

There is 1 hydroxide ion, on the reactant side

6 0

4 years ago