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2 years ago

. A base increases the OH- ion concentration of water.. True. False

2 answers:

8 0

It is a completely true statement that a <span>base increases the OH- ion concentration of water. The correct option among the two options that are given in the question is the first option. I hope that this is the answer that you were looking for and the answer has actually come to your desired help.</span>

FrozenT [24]2 years ago

3 0

Answer : The given statement is true.

Explanation :

Ionic product of water : It is defined as the product of the concentration of hydrogen ion and the concentration of hydroxide ion.

When the concentration of hydrogen ion and hydroxide ion are equal in the solution then the solution is neutral.

When the concentration of hydrogen ion are more in the solution then the solution is acidic in nature.

When the concentration of hydroxide ion are more in solution then the solution is basic in nature.

As per question, the addition of a base in the solution increases the concentration of hydroxide ion and decreases the concentration of hydrogen ion.

Hence, the given statement is true.

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Write a balanced chemical equation for the synthesis of ammonia from its elements including the word energy as a product

Katen [24]

Ammonia synthesis can be done by Haber process. N₂ gas and H₂ gas are used as the reactants. <span>The balanced reaction equation is
</span>N₂(g) + 3H₂(g) ⇄ 2NH₃(g) + energy

This is a reversible process and the conditions as follows,
1. Pressure should be 150 - 200 atm
2. Temperature is between 450 - 500 °C
3. Catalyst is iron

5 0

3 years ago

Hydrogen sulfide burns form sulfur dioxide:

Helga [31]

Answer: 404.04 kJ.

Explanation:

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

moles of $H_2S$

$\text{Number of moles}=\frac{26.7g}{34.1g/mol}=0.78moles$

$2H_2S(g)+3O_2(g)\rightarrow 2SO_2(g)+2H_2O(g)$ $\Delta H=-1036kJ$

According to stoichiometry :

2 moles of $H_2S$ on burning produces = 1036 kJ

Thus 0.78 moles of $H_2S$ on burning produces = $\frac{1036kJ}{2}\times 0.78=404.04$

Thus the enthalpy change when burning 26.7 g of hydrogen sulfide is 404.04 kJ.

7 0

2 years ago

What is an Ore? ufhfjfnf

Leya [2.2K]

Answer:

ore is naturally occuring solid material from which a metal or valuable mineral can be extracted

profitably.

3 0

2 years ago

In which conditions combination and displacement reaction takes place explain with example.

expeople1 [14]

<h2>Answer:</h2>

In <u>Combination reaction</u>, two or more elements combined to form one compound of different properties.

C(s) + O2(g) ⇢ CO2(g).
H2(g) + O2(g) ⇢ H20(l).

In <u>Displacement reation</u>, the high reactive element displaces the low reactive element and formed compound of different properties.

Fe(s) + CuSo4(aq) ⇢ FeSo4(aq) + Cu(s).
AgNO3(aq) + Cu(s) ⇢ CuNO3(aq) + Ag(s).

8 0

2 years ago

Read 2 more answers

Which statement is incorrect regarding the reaction of benzene with an electrophile? View Available Hint(s) A) The carbocation i

Leno4ka [110]

Answer:

The carbocation intermediate reacts with a nucleophile to form the addition product.

Explanation:

The reaction of benzene with an electrophile is an electrophillic substitution reaction. Here the electrophile replaces hydrogen. There is no formation of carbocation as intermediate in the reaction. Infact there is transition state where the electorphile attacks on benzene ring and at the same time the hydrogen gets removed from the benzene. So a transition carbocation is formed.

The general mechanism is shown in the figure.

i) Attack of the electrophile on the benzene (which is the nucleophile)

ii) The carbocation intermediate loses a proton from the carbon bonded to the electrophile.

iii) the carbocation formation is the rate determining step.

iv) There is no formation of addition product.

Thus the wrong statement is

The carbocation intermediate reacts with a nucleophile to form the addition product.

3 0

3 years ago