Ammonia synthesis can be done by Haber process. N₂ gas and H₂ gas are used as the reactants. <span>The balanced reaction equation is
</span>N₂(g) + 3H₂(g) ⇄ 2NH₃(g) + energy
This is a reversible process and the conditions as follows,
1. Pressure should be 150 - 200 atm
2. Temperature is between 450 - 500 °C
3. Catalyst is iron
Answer: 404.04 kJ.
Explanation:
To calculate the moles, we use the equation:
moles of

According to stoichiometry :
2 moles of
on burning produces = 1036 kJ
Thus 0.78 moles of
on burning produces =
Thus the enthalpy change when burning 26.7 g of hydrogen sulfide is 404.04 kJ.
Answer:
ore is naturally occuring solid material from which a metal or valuable mineral can be extracted
profitably.
<h2>
Answer:</h2>
In <u>Combination reaction</u>, two or more elements combined to form one compound of different properties.
- C(s) + O2(g) ⇢ CO2(g).
- H2(g) + O2(g) ⇢ H20(l).
In <u>Displacement reation</u>, the high reactive element displaces the low reactive element and formed compound of different properties.
- Fe(s) + CuSo4(aq) ⇢ FeSo4(aq) + Cu(s).
- AgNO3(aq) + Cu(s) ⇢ CuNO3(aq) + Ag(s).
Answer:
The carbocation intermediate reacts with a nucleophile to form the addition product.
Explanation:
The reaction of benzene with an electrophile is an electrophillic substitution reaction. Here the electrophile replaces hydrogen. There is no formation of carbocation as intermediate in the reaction. Infact there is transition state where the electorphile attacks on benzene ring and at the same time the hydrogen gets removed from the benzene. So a transition carbocation is formed.
The general mechanism is shown in the figure.
i) Attack of the electrophile on the benzene (which is the nucleophile)
ii) The carbocation intermediate loses a proton from the carbon bonded to the electrophile.
iii) the carbocation formation is the rate determining step.
iv) There is no formation of addition product.
Thus the wrong statement is
The carbocation intermediate reacts with a nucleophile to form the addition product.