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3 years ago

. A base increases the OH- ion concentration of water.. True. False

2 answers:

8 0

It is a completely true statement that a <span>base increases the OH- ion concentration of water. The correct option among the two options that are given in the question is the first option. I hope that this is the answer that you were looking for and the answer has actually come to your desired help.</span>

FrozenT [24]3 years ago

3 0

Answer : The given statement is true.

Explanation :

Ionic product of water : It is defined as the product of the concentration of hydrogen ion and the concentration of hydroxide ion.

When the concentration of hydrogen ion and hydroxide ion are equal in the solution then the solution is neutral.

When the concentration of hydrogen ion are more in the solution then the solution is acidic in nature.

When the concentration of hydroxide ion are more in solution then the solution is basic in nature.

As per question, the addition of a base in the solution increases the concentration of hydroxide ion and decreases the concentration of hydrogen ion.

Hence, the given statement is true.

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What's the difference between a mole of propane and a gram of propane? <br>

kobusy [5.1K]

B. A gram would have a lot more molecules of propane than a mole

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The fuel used to power the booster rockets on space shuttles is a mixture of aluminum metal and ammonium perchlorate. The follow

pishuonlain [190]

Answer:

Therefore 373 mole of Al produce 746 mole of water.

Explanation:

Given reaction is

3 Al+3NH₄ClO₄→Al₂O₃+AlCl₃+3NO+6H₂O

From the above reaction it is clear that 3 mole of Al produce 6 mole of water.

Therefore

3 mole of Al produce 6 mole of water.

1 mole of Al produce $\frac{6}{3}$ mole of water.

373 mole of Al produce $\frac{6\times 373}{3}$ mole of water.

= 746 mole of water.

Therefore 373 mole of Al produce 746 mole of water.

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Determine the empirical formula of the compound formed when 1.2g of magnesium reacts with 3.55g of chlorine.Take the molar mass

masha68 [24]

Explanation:

For Mg, (1.2 g Mg/24 g Mg) = 0.05 mol Mg.

For Cl, (3.55 g Cl/35.5 g Cl) = 0.1 mol Cl

So the ratio now is

Mg:Cl = 0.05 : 0.1 = 1:2

I got the 1:2 ratio by dividing both by the smallest number, which is 0.05 mol. Therefore, the empirical for formula of the substance is $MgCl_2$

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Ethan makes the table below to record his observations when mixing baking soda and vinegar in a beaker. Ethan claims that a chem

kozerog [31]

Answer: a

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