Discuss the environmental concerns regarding microfibre products

A hanging wire made of an alloy of nickel with diameter 0.19 cm is initially 2.8 m long. When a 59 kg mass is hung from it, the

Makovka662 [10]

Answer:

Young's modulus for this alloy of nickel is 1.997×10^11 N/m^2

Explanation:

Young's modulus = stress/strain

Stress = Force (F)/Area (A)

F = mg = 59 kg × 9.8 m/s^2 = 578.2 N

A = πd^2/4 = 3.142 × (0.19/100)^2/4 = 2.836×10^-6 m^2

Stress = 578.2/2.836×10^-6 = 2.039×10^8 N/m^2

Strain = extension/length = 2.86×10^-3 m/2.8 m = 1.021×10^-3

Young's modulus = 2.039×10^8/1.021×10^-3 = 1.997×10^11 N/m^2

4 0

3 years ago

What is the value of the energy (in Joules) stored by the mobile phone battery (capacity of 1.8 Ah), if it is rated at 3.7 V

joja [24]

Answer:

E=23,976 J

Explanation:

Given that

I = 1.8 Ah

Voltage = 3.7 V

We know that 1 h = 3600 s

I = 1.8 x 3600 A.s

I=6480 A.s

The energy in Jules given as

E= V. I

We know that unit of V.I is Watts ( J/s) and when multiple by seconds then we get Joules.

E=3.7 x 6480 Watt.s

E=23,976 J

Therefore the energy in joule will be 23,976 J.

4 0

3 years ago

Read 2 more answers

Which of the following can cause a flopping sound at the front of the engine

Irina-Kira [14]

B) timing chain too loose

3 0

3 years ago

When framing a building, a simple way to estimate the total amount of wall studs needed is to allow

Levart [38]

1+1=2
Solution
3:932(2)=61

4 0

3 years ago

A four-cylinder, four-stroke internal combustion engine has a bore of 3.7 in. and a stroke of 3.4 in. The clearance volume is 16

abruzzese [7]

Answer:

1) The three possible assumptions are

a) All processes are reversible internally

b) Air, which is the working fluid circulates continuously in a closed loop

cycle

c) The process of combustion is depicted as a heat addition process

2) The diagrams are attached

5) The net work per cycle is 845.88 kJ/kg

The power developed in horsepower ≈ 45374 hP

Explanation:

1) The three possible assumptions are

a) All processes are reversible internally

b) Air, which is the working fluid circulates continuously in a closed loop

cycle

c) The process of combustion is depicted as a heat addition process

2) The diagrams are attached

5) The dimension of the cylinder bore diameter = 3.7 in. = 0.09398 m

Stroke length = 3.4 in. = 0.08636 m.

The volume of the cylinder v₁= 0.08636 ×(0.09398²)/4 = 5.99×10⁻⁴ m³

The clearance volume = 16% of cylinder volume = 0.16×5.99×10⁻⁴ m³

The clearance volume, v₂ = 9.59 × 10⁻⁵ m³

p₁ = 14.5 lbf/in.² = 99973.981 Pa

T₁ = 60 F = 288.706 K

$\dfrac{T_{2}}{T_{1}} = \left (\dfrac{v_{1}}{v_{2}} \right )^{K-1}$

Otto cycle T-S diagram

T₂ = 288.706* $6.25^{0.393}$ = 592.984 K

The maximum temperature = T₃ = 5200 R = 2888.89 K

$\dfrac{T_{3}}{T_{4}} = \left (\dfrac{v_{4}}{v_{3}} \right )^{K-1}$

T₄ = 2888.89 / $6.25^{0.393}$ = 1406.5 K

Work done, W = $c_v$ ×(T₃ - T₂) - $c_v$ ×(T₄ - T₁)

0.718×(2888.89 - 592.984) - 0.718×(1406.5 - 288.706) = 845.88 kJ/kg

The power developed in an Otto cycle = W×Cycle per second

= 845.88 × 2400 / 60 = 33,835.377 kW = 45373.99 ≈ 45374 hP.

8 0

4 years ago