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slega [8]
3 years ago
12

Consider a continuous-flow, indraft supersonic wind tunnel, which uses a vacuum pump to draw atmospheric air from outside of the

wind tunnel building through a converging-diverging nozzle, to establish the supersonic flow in the test section. Assuming a standard day in Morgantown, WV (elevation of 961 feet) and a Mach number of 2.0 in the test section, compute the following:_____
a) The test section temperature
b) The test section pressure, assuming isentropic flow
c) The test section velocity
d) The change in the specific enthalpy of the air
Engineering
1 answer:
BigorU [14]3 years ago
3 0
I believe it’s B but I’m not sure
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Answer:

Use linking words.

Explanation:

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What are factor of safety for brittle and ductile material
galben [10]

Explanation:

Step1

Factor of safety is the number that is taken for the safe design of any component. It is the ratio of failure stress to the maximum allowable stress for the material.

Step2

It is an important parameter for design of any component. This factor of safety is taken according to the environment condition, type of material, strength, type of component etc.

Step3

Different material has different failure stress. So, ductile material fails under shear force. Ductile material’s FOS is based on yield stress as failure stress as after yield point ductile material tends to yield. Brittle material’s FOS is based on ultimate stress as failure stress.

The expression for factor of safety for ductile material is given as follows:

FOS=\frac{\sigma_{yp}}{\sigma_{a}}

Here,\sigma_{f} is yield stress and \sigma_{a} is allowable stress.

The expression for factor of safety for brittle material is given as follows:

FOS=\frac{\sigma_{ut}}{\sigma_{a}}

Here,\sigma_{ut} is ultimate stress and \sigma_{a} is allowable stress.

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3 years ago
Global Courier Services will ship your package based on how much it weighs and how far you are sending the package. Packages abo
denis23 [38]

Answer:

The code will be:

#include <stdio.h>

#include <stdlib.h>

main () {

double weight, shippingCharge, rate, segments;

int distance;

printf("Enter the weight: \n");

scanf("%lf", &weight);

printf("Enter the distance: \n");

scanf("%i", &distance);

if (weight <= 10) {

printf("Rate is $3.00 \n");

rate = 3;

} else {

printf("Rate is $5.00 \n");

rate = 5;

}

if (distance % 500 == 0) {

segments = distance / 500;

} else {

segments = distance / 500 + 1;

}

shippingCharge = rate * segments;

if (distance >1000) {

shippingCharge = shippingCharge + 10;

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printf("Your shipping charge is $%lf\n", shippingCharge);

system ("pause");

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8 0
3 years ago
10. Which of these requires a wheel alignment after replacement?
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C. Both; require a wheel alignment after replacement
5 0
3 years ago
Read 2 more answers
One kilogram of water fills a 150-L rigid container at an initial pressure of 2 MPa. The container is then cooled to 40∘C. Deter
lukranit [14]

The pressure of water is 7.3851 kPa

<u>Explanation:</u>

Given data,

V = 150×10^{-3} m^{3}

m = 1 Kg

P_{1} = 2 MPa

T_{2}  = 40°C

The waters specific volume is calculated:

v_{1} = V/m

Here, the waters specific volume at initial condition is v_{1}, the containers volume is V, waters mass is m.

v_{1} = 150×10^{-3} m^{3}/1

v_{1} = 0.15 m^{3}/ Kg

The temperature from super heated water tables used in interpolation method between the lower and upper limit for the specific volume corresponds 0.15 m^{3}/ Kg and 0.13 m^{3}/ Kg.

T_{1}= 350+(400-350) \frac{0.15-0.13}{0.1522-0.1386}

T_{1} = 395.17°C

Hence, the initial temperature is 395.17°C.

The volume is constant in the rigid container.

v_{2} = v_{1}= 0.15 m^{3}/ Kg

In saturated water labels for T_{2}  = 40°C.

v_{f} = 0.001008 m^{3}/ Kg

v_{g} = 19.515 m^{3}/ Kg

The final state is two phase region v_{f} < v_{2} < v_{g}.

In saturated water labels for T_{2}  = 40°C.

P_{2} = P_{Sat} = 7.3851 kPa

P_{2} = 7.3851 kPa

7 0
3 years ago
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