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3 years ago

11

g The human ear can perceive sounds with frequencies ranging from 20.0 Hz to 20000 Hz. If the speed of sound is 330 m/s in air a

nd 1500 m/s under water, what is the longest and shortest wavelength that can be heard in air and in water

1 answer:

garri49 [273]3 years ago

7 0

Answer: lamda max= 16,5m lamda min= 0,0165m (air)

lamda max= 75m, lamda min=0,075m (water)

Explanatin

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Answer:

$P_{sol}=50.4\ mm.Hg$

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According to given:

molecular mass of glycerin, $M_g=3\times 12+8+3\times 16=92\ g.mol^{-1}$

molecular mass of water, $M_w=2+16=18\ g.mol^{-1}$

∵Density of water is $0.992\ g.cm^{-3}= 0.992\ g.mL^{-1}$

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pressure of mixture, $P_x=55.32\ torr= 55.32\ mm.Hg$

temperature of mixture, $T_x=40^{\circ}C$

<em>Upon the formation of solution the vapour pressure will be reduced since we have one component of solution as non-volatile.</em>

<u>moles of water in the given quantity:</u>

$n_w=\frac{m_w}{M_w}$

$n_w=\frac{313.5}{18}$

$n_w=17.42 moles$

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$n_g=\frac{m_g}{M_g}$

$n_g=\frac{154}{92}$

$n_g=1.674 moles$

<u>Now the mole fraction of water:</u>

$X_w=\frac{n_w}{n_w+n_g}$

$X_w=\frac{17.42}{17.42+1.674}$

$X_w=0.912$

<em>Since glycerin is non-volatile in nature so the vapor pressure of the resulting solution will be due to water only.</em>

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