Answer:
1.44 atm
Explanation:
Step 1:
We'll begin by calculating the number of mole in 2,800,000 Liter of air.
I mole of air occupy 22.4L.
Therefore, Xmol of air will occupy 2800000L i.e
Xmol of air = 2800000/22.4
Xmol of air = 125000 moles
Step 2:
Determination of the pressure when the balloon is fully inflated .
This can be obtained as follow:
Number of mole (n) of air = 125000 moles
Volume (V) = 2800000 L
Temperature (T) = 120°C = 120°C + 273 = 393K
Gas constant (R) = 0.082atm.L/Kmol
Pressure (P) =.?
PV = nRT
Divide both side V
P= nRT/V
P= (125000x0.082x393) / 2800000
P = 1.44 atm
Therefore, the pressure of the air when the balloon is fully inflated is 1.44 atm
Answer:
14.91 K.
Explanation:
- To solve this problem, we can use the following relation:
<em>Q = m.c.ΔT,</em>
where, Q is the amount of heat transferred to water.
m is the mass of the amount of water (m = 2.0 kg = 2000.0 g).
c is the specific heat capacity of water (c = 4.2 J/g.K).
ΔT is the change in temperature due to the transfer of butane burning.
- To determine Q that to be used in calculation:
Q from 4.000 g of butane is completely burned is - 198.3 kJ = 198300 J.
<em>The negative sign</em><em> symbolizes the the enthalpy change is </em><em>exothermic</em><em>, which means that </em><em>the</em><em> </em><em>energy is released</em><em>.
</em>
- Note that only 63.15% of the energy generated is actually transferred to the water.
∴ Q (the amount of heat transferred to water) = (198300 J)(0.6315) = 125226.45 J.
- Now, we can obtain the change in temperature:
∴ ΔT = Q/m.c. = (125226.45 J) / (2000.0 g)(4.2 J/g.K) = 14.9079 K ≅ 14.91 K.
<em>This means that the temperature is increased by 14.91 K.</em>
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Answer : The concentration to a mole fraction in parts per billion (ppb) is, 350 ppb
Explanation :
As we are given that the concentration of chloroform is, .
Now we have to convert it into parts per billion (ppb).
As we know that,
and,
So,
Thus, the concentration to a mole fraction in parts per billion (ppb) is, 350 ppb
Answer:
C
Explanation:
The atom has an electron configuration of 1s²2s²2p⁶3s²3p⁵.
The total numbe of electrons present in the shell is 17 electrons. To determine the group of the atom, we have to check what orbital did the last electron stop.
If it's in S-orbital, then we automatically knows it's an s-block element which could either be group 1 or 2 and can still be furthered down to know which group it's in.
But in this case, the last electron is in s-orbital. To determine the group number of p-orbitals, we'll have to consider the preceding s-orbital and add it to it, then count it in 10s.
For example, if the last two orbital is 3s² 3p¹, 2 + 1 = 3, add ten (10) to it = 13. Hence the element is in group 13.
In this case, we have 3s² 3p⁵ = 2 + 5 = 7 + 10 = 17.