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djverab [1.8K]
3 years ago
12

He free energy of a gas depends on __________. (select all correct answers) partial pressure of the gas van der waals constant f

or the gas temperature of the gas viscosity of the gas
Chemistry
1 answer:
Black_prince [1.1K]3 years ago
4 0
Viscosity of the gas
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1 question you still have about the concept
allochka39001 [22]

Answer:

what concept?

Explanation:

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2 years ago
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In the chemical reaction: NaOH (s) + H2O Na+ (aq) + OH- (aq), which substance (or substances) is in solution? A. Na+ (aq) only B
bonufazy [111]

Answer:

in a chemical reaction of NaOH with H2O, after NaOH is completely disassociated, we will find Na+ and OH- ions in the solution. (option C).

Explanation:

In a reaction where NaOH is added to H2O.

NaOH is considered a strong base, this means that in an aqueous solution ( in water) it's  able to completely disassociate in ions.

There will not remain any NaOH in the solution. This means option D is not correct.

The ions in which NaOH will disassociate are : NaOH → Na+ + OH-

These ions we will find in the solution.

Not only Na+ because NaOH is a strong base, so there will be a lot of OH- ions as well in solution.

This means in a chemical reaction of NaOH with H2O, after NaOH is completely disassociated, we will find Na+ and OH- ions in the solution.

3 0
2 years ago
The Lewis dot model of a molecule is shown.
Katen [24]

Answer:

Carbon has a total of four bonded pairs of electrons around it.

Explanation:

Since there are four "lines" around the C (which stands for Carbon), we can conclude that Carbon has a total of four bonded pairs of electrons around it.

3 0
3 years ago
Match these items.
dolphi86 [110]

g - Measurement of Mass

m² - Measurement of Area

m³ - Measurement of Volume

km- Measurement of Length

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3 years ago
A compound with molecular formula C5H10O2 has the following 1H NMR spectrum: 1.15 (t, 3H), 1.25 (t, 3H), 2.33 (q, 2H), 4.13 (q,
Vilka [71]

Answer:

Ethyl propionate

Explanation:

Calculating the double bond equivalence as:

DBE =  C - (H/2) - (X/2) + (N/2) +1

Where  

C is the number of carbon atoms

N is the number of nitrogen atoms

X is the number of halogens

H is the number of hydrogen atoms

So, according to the formula, C_5H_{10}O_2

DBE =  5 - (10/2) - (0/2) + (0/2) +1 = 1

It means there is one double bond or one ring.

from the NMR signal, it is clear that compound has two triplet and two quardrate group that means two -CH3 and two -CH2 groups are present.

From the splitting information, it is clear that each the -CH2- group is next to a -CH3, and vice-versa. In this case ring structure is not possible.

The chemical shift of two protons 4.13 ppm(q, 2H) is for protons next to an O atom, therefore, compound must have

-OCH_2CH_3.

Then the signal at 2.33 is for a -CH2-group next to a C=O. So compound must have a structure CH3-CH2-C=O. Now, there is only one way to complete the structure - by bonding the O to the C=O carbon.

So the compound is ethyl propionate

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2 years ago
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