Question

A 3.00 kilogram mass is thrown vertically upward with an initial speed of 9.80 meters per second.What is the maximum height this object will reach ?

Answer 1

Answer:

4.895 m

Explanation:

at the maximum height, the vertical speed will be zero.

u=9.80 m/s

Since it is travelling upwards, a =-9.81 m/s^2

At max height, v= 0 m/s

Therefore by the formula, v^2 = u^2 + 2ax, calculate x

0 = 9.80^2 + 2 (-9.81) x

x = 96.04/19.62

x = 4.895 m