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Phoenix [80]
3 years ago
15

A 3.00 kilogram mass is thrown vertically upward with an initial speed of 9.80 meters per second.What is the maximum height this

object will reach ?
Physics
1 answer:
Tamiku [17]3 years ago
5 0

Answer:

4.895 m

Explanation:

at the maximum height, the vertical speed will be zero.

u=9.80 m/s

Since it is travelling upwards, a =-9.81 m/s^2

At max height, v= 0 m/s

Therefore by the formula, v^2 = u^2 + 2ax, calculate x

0 = 9.80^2 + 2 (-9.81) x

x = 96.04/19.62

x = 4.895 m

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Stells [14]

Answer:

9.6J+88.2J=97.8J

Explanation:

Here the velocity of the seagull is given,mass is given and its height.

We have to find its mechanical energy my friend.

Mechanical energy=kinetic energy + potential energy.

First we will find kinetic energy.

For calculating kinetic energy we need mass and velocity,which are given here.

So, Ek=

1 \div 2mv {?}^{2}

So by substituting the values we get 9.6J.

Now we find the potential energy which is mgh.

By substituting the values we get 88.2J.

Then we add both of those and get 97.8J

I hope this satisfies you and make sure you contact me if it doesn't

7 0
4 years ago
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Answer:

V_m = 12.78 km/hr

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given,

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for dynamic similarities

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  (\dfrac{70}{\sqrt{120}}) = (\dfrac{V_m}{\sqrt{4}})

          V_m = 12.78 km/hr

hence, the velocity of model will be 12.78 km/h

6 0
4 years ago
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Powdered sugar dissolves faster compare to the sugar cube. Because sugar cube has less surface area (the granules are tightly packed) compared to powdered sugar  

6 0
3 years ago
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