188m - 556m is the wavelength range for AM radio.
2.77 - 3.40m is the wavelength range for FM radio.
1) For AM radio
f(max) = 1600 × 10³ Hz
f(min) = 540 ×10³Hz
c = fλ
λ = c/f where,
c = speed of light
f = frequency
λ= wavelength
So,
λ(min) = 3 × 
/ 1600 × 10³ = 188 m
λ(max) = 3 × 10⁸/540 ×10³ = 556 m
So wavelength range of AM radio is 188 m - 556m
2) For FM radio
f(max) = 108 × 10⁶ Hz
f(min) = 88 × 10⁶ Hz
λ(min) = 3 × 10⁸ / 108 × 10⁶ = 2.77 m
λ(max) = 3 × 10⁸ / 88 × 10⁶ = 3.40 m
So wavelength range of FM radio is 2.77m - 3.40m
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Answer:
I think it is C.
Explanation:
I took a 12 question quiz in USA TP and made a 92%. It won't let me see which one I missed though.
Look up habitat fragmentation and think about how well it answers the question given.
The average current density is 7.6 × 10⁵ A/m².
To calculate the current density current will be 2.4 A.
Diameter of a wire = 2mm.
The cross-sectional area of the wire is given by r = d/2
where r is the radius of the wire.
Then, the cross-sectional area is = 0.00000314159265
= 3.1 × 10⁻⁶ m².
<h3>
What is average current density?</h3>
Consider a current carrying conductor, the current density depends upon the current flow in the conductor. If the current flow in the conductor will be high then the current density will also be high. Using the average current flowing through the conductor, the average current density will be found.
Average current density j = I / A Ampere/ meter².
By substituting the values in the formula,
j = 2.4 / ( 3.1 × 10⁻⁶)
= 7.6 × 10⁵ A/m².
Hence, the current density can be calculated.
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Answer:
The gravitational force is much larger than the electrical force for any distance between the particles.
Explanation:
