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Anestetic [448]
3 years ago
5

What acceleration would you expect a 100 kg individual to experience from a 1000N force?

Physics
1 answer:
german3 years ago
7 0

Answer: 10 m/2^2

F=ma

Explanation:

Force = 1000N

1 N is 1 (kg*m/s^2)

Mass = 100kg

F=ma

a = F/m

a = (1000kg*m/s^20/(100kg)

a = 10 m/s^2

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A flea jumps by exerting a force of 1.09 ✕ 10−5 N straight down on the ground. A breeze blowing on the flea parallel to the grou
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Answer:

a= 17.877 m/s² : Magnitude of the acceleration of the flea

β = 88.21°  :  Direction  of the acceleration of the flea

Explanation:

Conceptual analysis

We apply Newton's second law:

∑F = m*a (Formula 1)

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

Problem development

Look at the flea free body diagram in the attached graphic

The acceleration is presented in the direction of the resultant force (R) applied over the flea .

R= \sqrt{(F_{x})^{2} + (F_{y})^{2} }

R= \sqrt{(10.9)^{2}+(0.340)^{2}  } *10^{-6} N

R= 10.905*10⁻⁶ N

We apply the formula (1) to calculate the magnitude of the acceleration of the flea

∑F = m*a   m = 6.1 * 10⁻⁷ kg

R = m*a

a= R/m

a= (10.905*10⁻⁶) /  (6.1 * 10⁻⁷ )

a= 17.877 m/s²

β: Direction and magnitude of the acceleration of the flea

\beta = tan^{-1} (\frac{F_{y} }{F_{x} } )

\beta = tan^{-1} (\frac{10.9*10^{-6} }{0.340*10^{-6} } )

β = 88.21°

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