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3 years ago

What acceleration would you expect a 100 kg individual to experience from a 1000N force?

Physics

1 answer:

german3 years ago

7 0

Answer: 10 m/2^2

F=ma

Explanation:

Force = 1000N

1 N is 1 (kg*m/s^2)

Mass = 100kg

F=ma

a = F/m

a = (1000kg*m/s^20/(100kg)

a = 10 m/s^2

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3 years ago

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Answer:

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According to the question, the separation between two parallel plates, plate A and plate B (say) = d

The electric potential at a distance d due to 'Q' is:

$V = \frac{1}{4\pi\epsilon_{o}}.\frac{Q}{d}$

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Similar is the case with plate B:

$V_{B} = \frac{1}{4\pi\epsilon_{o}}.\frac{q}{\frac{d}{2}}$

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