Answer:
T = 25 N
Explanation:
The question says that "A 25 n block is suspended by a wire from the ceiling vitamin the tension that appears in the wire
?"
Weight of the block, W = 25 N
Weight of a body acts in downward direction and tension acts in upward direction. It would mean that,
Tension = weight of the block
T = mg
T = 25 N
Hence, the tension in the wire is 25 N.
Answer:
Force / mass
Explanation:
Divide mass on both sides to get acceleration by itself leaving you with mass below force hence divide force by mass
First establish the summation of the forces acting int the
ladder
Forces in the x direction Fx = 0 = force of friction (Ff) –
normal force in the wall(n2)
Forces in the y direction Fy =0 = normal force in floor (n1)
– (12*9.81) –( 60*9.81)
So n1 = 706.32 N
Since Ff = un1 = 0.28*706.32 = 197,77 N = n2
Torque balance along the bottom of the ladder = 0 = n2(4 m) –
(12*9.81*2.5 m) – (60*9.81 *x m)
X = 0.844 m
5/ 3 = h/ 0.844
H = 1.4 m can the 60 kg person climb berfore the ladder will
slip
Answer:
Explanation:
1 full revolution is 
let \theta be the angle of Ron's position.
At t = 0. 
one full revolution occurs in 12 sec, so his angle at t time is
r is radius of circle and it is given as
for r = 30 sec
however, that is centered at (0,0) and the positioned at time t = 0 is (30,0). it is need to shift so that the start position is (30,45). it can be done by adding to y
Answer:
299.88 kgm²/s
499.758 kgm²/s
Explanation:
R = Radius of merry-go-round = 1.63 m
I = Moment of inertia = 196 kgm²
= Initial angular velocity = 1.53 rad/s
m = Mass of person = 73 kg
v = Velocity = 4.2 m/s
Initial angular momentum is given by
The initial angular momentum of the merry-go-round is 299.88 kgm²/s
Angular momentum is given by
The angular momentum of the person 2 meters before she jumps on the merry-go-round is 499.758 kgm²/s
