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maksim [4K]
3 years ago
11

The red shift of visible light waves that is observed by astronomers on Earth is used to determine the

Physics
1 answer:
Kryger [21]3 years ago
3 0
This actually means that the object which is emitting light spectrum is moving away from us.. how do you know that ? well.. it is clearly mentioned that it is a red shift so the wavelengths will stretched more . and thus the spectrum turns more reddish as it has higher wavelengths .. hence so called red shifts
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Why has the model of the atom changed over time?
Makovka662 [10]
<span>A.
The model of the atom evolved as scientists have made new discoveries.</span>
7 0
3 years ago
A satellite orbits the earth a distance of 1.50 × 107 m above the planet's surface and takes 8.65 hours for each revolution abou
kupik [55]

Answer:

The acceleration of the satellite is 0.87 m/s^{2}

Explanation:

The acceleration in a circular motion is defined as:

a = \frac{v^{2}}{r}  (1)

Where a is the centripetal acceleration, v the velocity and r is the radius.

The equation of the orbital velocity is defined as

v = \frac{2 \pi r}{T} (2)

Where r is the radius and T is the period

For this particular case, the radius will be the sum of the high of the satellite (1.50x10^{7} m) and the Earth radius (6.38x10^{6} m) :

r = 1.50x10^{7} m+6.38x10^{6}m

r = 21.38x10^{6}m

Then, equation 2 can be used:

T = 8.65 hrs \cdot \frac{3600 s}{1hrs} ⇒ 31140 s

v = \frac{2 \pi (21.38x10^{6}m)}{31140s}

v = 4313 m/s

Finally equation 1 can be used:

a = \frac{(4313m/s)^{2}}{21.38x10^{6}m}    

a = 0.87 m/s^{2}

Hence, the acceleration of the satellite is 0.87 m/s^{2}

6 0
3 years ago
The wave shown below is produced in a rope.
Kay [80]

Answer:

<h3>B) A dot vector drawn up and vector drawn down.</h3>

Explanation:

Brainliest?

6 0
3 years ago
Read 2 more answers
A scientist wants to model an internal organ with connective tissue as a mass on a spring. The mass of the organ is 2.0 kg, and
vichka [17]

Answer:

Spring constant, k = 5483.11 N/m

Explanation:

It is given that,

Mass of the organ, m = 2 kg

The natural period of oscillation is, T = 0.12 s

Let k is the spring constant for the spring in the scientist's model. The period of oscillation is given by :

T=2\pi\sqrt{\dfrac{m}{k}}

k=\dfrac{4\pi^2 m}{T^2}

k=\dfrac{4\pi^2 \times 2\ kg}{(0.12\ s)^2}

k = 5483.11 N/m

So, the  spring constant for the spring in the scientist's model is 5483.11 N/m.

5 0
3 years ago
A circular parallel plate capacitor is constructed with a radius of 0.52 mm, a plate separation of 0.013 mm, and filled with an
olya-2409 [2.1K]

Answer:

289282

Explanation:

r = Radius of plate = 0.52 mm

d = Plate separation = 0.013 mm

A = Area = \pi r^2

V = Potential applied = 2 mV

k = Dielectric constant = 40

\epsilon_0 = Electric constant = 8.854\times 10^{-12}\ \text{F/m}

Capacitance is given by

C=\dfrac{k\epsilon_0A}{d}

Charge is given by

Q=CV\\\Rightarrow Q=\dfrac{k\epsilon_0AV}{d}\\\Rightarrow Q=\dfrac{40\times 8.854\times 10^{-12}\times\pi \times (0.52\times 10^{-3})^2\times 2\times 10^{-3}}{0.013\times 10^{-3}}\\\Rightarrow Q=4.6285\times 10^{-14}\ \text{C}

Number of electron is given by

n=\dfrac{Q}{e}\\\Rightarrow n=\dfrac{4.6285\times 10^{-14}}{1.6\times10^{-19}}\\\Rightarrow n=289281.25\ \text{electrons}

The number of charge carriers that will accumulate on this capacitor is approximately 289282.

6 0
3 years ago
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