Answer:
Explanation:
Given
radius of circle=1.4 m
Height of stone above ground=1.5 m
Horizontal distance(R)=10 m
It is given at the time of break stone flies horizontally thus stone to cover a height of 1.5 m in time t before reaching ground

t=0.55 s
Initial horizontal velocity at the time of break is given by u


u=18.07 m/s
Therefore magnitude of centripetal acceleration is given by

Answer
given,
For helium
Volume,V = 46 L
Pressure,P = 1 atm
Temperature,T = 25°C = 273 +25 = 298 K
R=0.0821 L . atm /mole.K
n₁ = ?
number of moles
we know
P V = n R T

n₁ = 1.89 moles
For oxygen
Volume,V = 12 L
Pressure,P = 1 atm
Temperature,T = 25°C = 273 +25 = 298 K
R=0.0821 L . atm /mole.K
n₂ = ?
number of moles
we know
P V = n R T

n₂ = 0.49 moles
Total volume of tank = 5 L
temperature of tank = 298 K
Partial pressure of helium


P₁ = 9.25 atm
Partial pressure of oxygen


P₂ = 2.39 atm
total pressure
P = P₁ + P₂
P = 9.25 + 2.39
P = 11.64 atm
Answer:
Hydraulic pressure exerted on glass slab, ρ=10 atm
Bulk modulus of glass, B=37×10^9 Nm^−2
Bulk modulus, B=P/(ΔV/V)
where,
ΔV/V= Fractional change in volume
ΔV/V=P/B
=10×1.013×10^5 /(37×10 ^9)
=2.73×10^-5
Therefore, the fractional change in the volume of the glass slab is 2.73×10^-5
Hope it helps
Answer:
A. Technician A only
Explanation:
The camshaft opening ramp is what opens the valve, it starts at the basement of the inner circle and closes at the nose while the camshaft closing ramp allows for closing a valve starts at the nose and closes at the inner base circle. Valve clearance on an engine are performed when closing a valve, and is completed when the valve lifter or follower is on the inner base circle of the camshaft lobe.
C. Quarts watches is the correct answer