Equation is:
Ca(NO3)2 + Na3PO4 —> NaNO3 + Ca3(PO4)2
Balance it out
3Ca(NO3)2 + 2Na3PO4 —> 6NaNO3 + Ca3(PO4)2
You have 96.1g of Calcium Nitrate
Moles = Mass/Molar Mass
Molar mass of Calcium Nitrate is 164.088 g/mol
96.1g / 164.088 g/mol =0.586 moles
Mole ratio is 3:1
Therefore 0.586/3 moles of calcium phosphate
Moles x molar mass = mass
0.586/3 x 310.18 g/mol = 60.6~g roughly as theoretical yield
<span> We are given with the rate constant of a first-order decomposition of n2o which is equal to 3.40 s-1. Half life of the radioactive material can be determined through the formula: t= ln2 /k where t is the half life of the material. t then upon substitution is equal to 0.2048 s. </span>
The balanced chemical equation will b
N2H4 + 2 H2O2-> N2 + 4H2O
so first of all we have to find the limiting reactant.
so for this
9.24 g H2O2 ( 1 mol / 34.02 g mass of H2O2 )
= 0.27 mol H2O2
Now
6.56 g of N2H4 ( 1mol / 32.06) = 0.20 mol N2H4
so from the above reaction we found 1:2 ratio of the reactants
so the limiting reactant is hydrogen peroxide. by using this we will find the amount of N2 produced.
so that will be
<span>0.27 mol H2O2 ( 1 mol N2 / 2 mol H2O2 ) ( 14.01 g N2 / 1 mol N2)
=1.89 g N2
hope it helps</span>
I think the answer is b because a reactant is the start of a chemical reaction and a product is the end of it.
