Answer:
Value of h greater than 5.4 will make inequality false.
Step-by-step explanation:
This question is incomplete; here is the complete question.
The Jones family has saved a maximum of $750 for their family vacation to the beach. While planning the trip, they determine that the hotel will average $125 a night and tickets for scuba diving are $75. The inequality can be used to determine the number of nights the Jones family could spend at the hotel 750 ≥ 75 + 125h. What value of h does NOT make the inequality true?
From the given question,
Per night expense (expected) = $125
If Jones family stays in the hotel for 'h' days then total expenditure on stay = $125h
Charges for scuba diving = $75
Total charges for stay and scuba diving = $(125h + 75)
Since Jones family has saved $750 for the vacation trip so inequality representing the expenses will be,
125h + 75 ≤ 750
125h ≤ 675
h ≤ 
h ≤ 5.4
That means number of days for stay should be less than equal to 5.4
and any value of h greater than 5.4 will make the inequality false.
Answer:
Since the calculated value of z= -1.496 does not fall in the critical region z < -1.645 we conclude that the new program is effective. We fail to reject the null hypothesis .
Step-by-step explanation:
The sample proportion is p2= 7/27= 0.259
and q2= 0.74
The sample size = n= 27
The population proportion = p1= 0.4
q1= 0.6
We formulate the null and alternate hypotheses that the new program is effective
H0: p2> p1 vs Ha: p2 ≤ p1
The test statistic is
z= p2- p1/√ p1q1/n
z= 0.259-0.4/ √0.4*0.6/27
z= -0.141/0.09428
z= -1.496
The significance level ∝ is 0.05
The critical region for one tailed test is z ≤ ± 1.645
Since the calculated value of z= -1.496 does not fall in the critical region z < -1.645 we conclude that the new program is effective. We fail to reject the null hypothesis .
Answer:
Yes, the triangles are simirar with a scale factor of 3/2.
Step-by-step explanation:
We find the scale factor by dividing corresponding sides:
12/8=3/2
18/12=3/2
24/16=3/2
So, if I'm understanding you correctly, f(x)=x^2 divided by 3x+x, or
f(x) = (x^2)/(3x+x)
f(6) --> plug the 6 in to all values of x --> f(6) = (6^2)/(3×6 + 6) = 36/(18+6)
= 36/24 --> both are divisible by 12, so 36/12=3 and 24/12=2, now we have the reduced (simplified) answer:
f(6) = 3/2, or 1 1/2, or 1.5
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