Answer:
- Driving surface area as subject to differential pressures
- How to achieve continuous rotation
- Mechanical connections
Explanation:
The general stages of thinking when designing a system are;
- First understanding the problem that requires you to design a solution
- Defining the problem that needs to be solved. In this case is to design an efficient hydraulic engine for a motorboat
- Research to find any available solutions for similar problems
- Idea of the solution
- A prototype to try solve the challenge
- Selecting and adjusting the prototype as you implement the solution.
For a hydraulic engine design, the following designing parts are vital;
- Driving surface area as subject to differential pressures
- How to achieve continuous rotation
- Mechanical connection
Pressures are important due to motor displacements. Fuel burns in the cylinder to cause power through fuel gases burning and expansion which is the four-stroke cycle. Continuous rotation will come in the design considerations through reciprocating motions of pistons into rotary motions. Mechanical connections are vital especially in crank shaft turns, gear box that turns horizontal motions to spinning motions and finally the propeller that drives the boat on the water.
I assume this is a wood shop question:
You may not work on any equipment if the TEACHER is not present in the room.
Answer: (a) 0,142 (b) 52.99 (c) 2.83 (d) 88.26
Explanation:
If the refrigarating capacity is 150kw
(a) the mass flow rate of refrigerant, in kilograms per second is 0.142
(b) the power input to the compressor, in kilowatts is 52.99
(c) the coefficient of performance is 2.83
(d) the isentropic compressor efficiency is 68.6 per cent
Answer:
Explanation:
The formula for critical stress is
K is the plane strain fracture toughness
Y is dimensionless parameters
We are to Determine the Critical stress
Now replacing the critical stress with 54.8
a with 0.2mm = 0.2 x 10⁻³
Y with 1
The fracture will not occur because this material can handle a stress of 2186.20Mpa before fracture. it is obvious that is greater than 2023Mpa
Therefore, the specimen does not failure for surface crack of 0.2mm
