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Westkost [7]
3 years ago
5

Inverse Variation

Mathematics
1 answer:
AURORKA [14]3 years ago
5 0
(1)\\R\cdot I=a\ \ \ \ and\ \ \ 50\cdot 0.15=a\\\\ \ \Rightarrow\ \ \ a=7.5\ \ \ \Rightarrow\ \ I= \frac{7.5}{R} \ \ \ \Rightarrow\ \ \ Ans.\ A.\\\\(2)\\x\cdot y=a\ \ \ and\ \ \ 8\cdot6=a\\\\ \ \Rightarrow\ \ \ a=48\ \Rightarrow\ \ \  xy=48\ \ \ \Rightarrow\ \ \ 10y=48\ \Rightarrow\ \ \ y=4.8\ \Rightarrow\ \ \ Ans.\ D.\\\\(3)\\xy=-12\ \ \Rightarrow\ \ \ constant=-12\ \ \Rightarrow\ \ \ Ans.\ D.\\\\

(4)\\xy=-12\\\\e.g.:\ \ \ x=3\ \ and\ \ y=-4\ \ \ \ or\ \ \ \ x=-3\ \ and\ \ y=4\ \ \Rightarrow\ \ Ans.\ A.\\\\(5)\\V\cdot T=a\ \ \ and\ \ \ 18\cdot 3=a\\\\ \ \ \Rightarrow\ \ \ a=54\ \ \ \Rightarrow\ \ \ V\cdot T=54\ \ \ \Rightarrow\ \ \ V= \frac{54}{T} \ \ \ \Rightarrow\ \ \ Ans.\ C.
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C is 666666688888 from my lookings. Jk
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3 years ago
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Aviation:
kolezko [41]

Change in altitude:

42,000 - 18,000 = 24,000 feet

Rate of change  = 24,000 feet / 12 minutes = 2,000 feet per minute

Because the plane was going down, the rate of change would be negative.

The rate would be -2,000 feet per minute.

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3 years ago
17. Which of the following is the correct formula for finding power in a DC circuit? A. P = I2R B. P = VR C. P = IR D. P = V2I
netineya [11]

Answer:

Choice A. P = I² · R where

  • P is the power in the DC circuit,
  • I is the current through the circuit, and
  • R is the total resistance of the circuit.

Step-by-step explanation:

Electrical power is the rate at which the electrical force does work. So what is electrical work? That's the work W that the electrical force do when it moves charges Q across a potential difference V:

W = V\cdot Q.

The power is the rate at which the electrical force do the work:

\displaystyle P = \frac{W}{t} = V \cdot \frac{Q}{t}.

On the other hand, current I is the charge through a cross-section of the circuit in unit time. By the definition of current:

\displaystyle\frac{Q}{t} = I.

\displaystyle P =V \cdot \frac{Q}{t} = V\cdot I.

Consider Ohm's Law:

V = I \cdot R.

Therefore

\displaystyle P = V\cdot I = (I \cdot R) \cdot I = I^{2}\cdot R.

6 0
3 years ago
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Are these questions biased or not???​
o-na [289]

Answer:

No.

Step-by-step explanation:

Biased means extremely on one side, so no, the questions are not biased.

3 0
3 years ago
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15. Suppose a box of 30 light bulbs contains 4 defective ones. If 5 bulbs are to be removed out of the box.
Naddika [18.5K]

Answer:

1) Probability that all five are good = 0.46

2) P(at most 2 defective) = 0.99

3) Pr(at least 1 defective) = 0.54

Step-by-step explanation:

The total number of bulbs = 30

Number of defective bulbs = 4

Number of good bulbs = 30 - 4 = 26

Number of ways of selecting 5 bulbs from 30 bulbs = 30C5 = \frac{30 !}{(30-5)!5!} \\

30C5 = 142506 ways

Number of ways of selecting 5 good bulbs  from 26 bulbs = 26C5 = \frac{26 !}{(26-5)!5!} \\

26C5 = 65780 ways

Probability that all five are good = 65780/142506

Probability that all five are good = 0.46

2) probability that at most two bulbs are defective = Pr(no defective) + Pr(1 defective) + Pr(2 defective)

Pr(no defective) has been calculated above = 0.46

Pr(1 defective) = \frac{26C4  * 4C1}{30C5}

Pr(1 defective) = (14950*4)/142506

Pr(1 defective) =0.42

Pr(2 defective) =  \frac{26C3  * 4C2}{30C5}

Pr(2 defective) = (2600 *6)/142506

Pr(2 defective) = 0.11

P(at most 2 defective) = 0.46 + 0.42 + 0.11

P(at most 2 defective) = 0.99

3) Probability that at least one bulb is defective = Pr(1 defective) +  Pr(2 defective) +  Pr(3 defective) +  Pr(4 defective)

Pr(1 defective) =0.42

Pr(2 defective) = 0.11

Pr(3 defective) =  \frac{26C2  * 4C3}{30C5}

Pr(3 defective) = 0.009

Pr(4 defective) =  \frac{26C1  * 4C4}{30C5}

Pr(4 defective) = 0.00018

Pr(at least 1 defective) = 0.42 + 0.11 + 0.009 + 0.00018

Pr(at least 1 defective) = 0.54

3 0
3 years ago
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