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Harlamova29_29 [7]
3 years ago
14

A 3,600 kg sphere is located at a distance of 5.2 m from a 1,200 kg sphere.what is the gravitational force between the two spher

es?
Physics
1 answer:
storchak [24]3 years ago
5 0
Gravitational push or pull.
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Cubes are three-dimensional square shapes that have equal sides. What is the density of a cube that has a mass of 12.6 g and a m
sweet-ann [11.9K]
 I got 3.07cm³. Its just 12.6 divided by 4.1
6 0
3 years ago
A rope is shaken and produces 2 waves each second. Calculate the time period of the rope waves.
motikmotik

Answer:

0.5 s

Explanation:

From the question given above, the following data were obtained:

Number of circle (n) = 2

Time (t) = 1 s

Period =?

Period of a wave is simply defined as the time taken to make one complete oscillation. Mathematically, it can be expressed as:

T = t / n

Whereb

T => is the period

t => is the space time

n => is the number of circle or oscillation.

With the above formula, we can obtain the period of the wave as follow:

Number of circle (n) = 2

Time (t) = 1 s

Period =?

T = t / n

T = 1 / 2

T = 0.5 s

Thus, the period of the wave is 0.5 s

7 0
3 years ago
A proton is accelerated from rest through a potential difference V0 and gains a speed v0. If it were accelerated instead through
Neporo4naja [7]

Answer:

Explanation:

Let the charge on proton be q .

energy gain by proton in a field having potential difference of V₀

= V₀ q

Due to gain of energy , its kinetic energy becomes 1/2 m v₀²

where m is mass and v₀ is velocity of proton

V₀ q = 1/2 m v₀²

In the second case , gain of energy in electrical field

= 2 V₀q , if v be the velocity gained in the second case

2 V₀q = 1/2 m v²

1/2 m v² = 2 V₀q = 2 x 1/2 m v₀²

mv² = 2  m v₀²

v = √2 v₀

6 0
3 years ago
Why is it that the two possible faults with inductors are short circuit and open circuit?
lukranit [14]
These are the most common type of faults not just inductors but also with other elements too like resistors,transformers, generators etc.
open circuit fault means the flow of current is disrupted some how in the circuit and the circuit stops operating. and for short circuit fault the current in the system will be pretty high and this short circuit current or fault current will always run back to the fault location, if the inductor got short circuited somehow then the fault current will only run through it because it will then provide a very low impedence path
5 0
3 years ago
50 POINTS‼️‼️‼️‼️‼️
Inessa05 [86]

Answer:

Explanation:

the yellow box is -5

3 0
3 years ago
Read 2 more answers
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