Answer:
C released to the environment
Explanation:
I just did it in class
Answer: A volume of 600 mL of 3.0 M
solution can be prepared by using 100.0 mL OF 18 M
.
Explanation:
Given:
= ?, 
, 
Formula used to calculate the volume is as follows.

Substitute the values into above formula as follows.

Thus, we can conclude that a volume of 600 mL of 3.0 M
solution can be prepared by using 100.0 mL OF 18 M
.
Answer:
There are two types of mixtures: heterogeneous and homogeneous. Heterogeneous mixtures have visually distinguishable components, while homogeneous mixtures appear uniform throughout. The most common type of homogenous mixture is a solution, which can be a solid, liquid, or gas.
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Answer:
-304.1
I had this question and that’s what I got
Chadwick did!
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