Torque = r x F
|F| = mg = 60 * 10 N = 600 N ( assuming g ~ 10m/s^2)
distance of fulcrum = torque / Force = 90/600 m = .15 m.
Answer:
<h2>Angular Displacement 6.28 radians</h2>
Explanation:
for circular motion we are expected to solve for Angular Displacement it is measured in radian
Measurement of Angular Displacement.
we can measure it using the following relation
∅= s/r
where
s = the distance travelled by the body, and
r = radius of the circle along which it is moving.
given that
circumference c, s= 400 m
r= ?
we have to solve for the radius
we know that circumference

400= 2*3.142*r
400= 6.282*r
divide both sides by 6.284 we have
400/6.284
r= 63.63 m
Angular displcament
∅= 400/63.63
∅= 6.28 radians
Answer:
x = 0.237
y = 0.0789
Explanation:
Vector with direction 18.4° and magnitude 0.250 has x and y components of:
x = 0.250 cos 18.4°
x = 0.237
y = 0.250 sin 18.4°
y = 0.0789
Answer:

Explanation:
Given:
- mass of water,

- initial temperature of water,

- initial temperature of pan,

- mass of pan,

- mass of water evapourated,

- specific heat of water,

- specific heat of aluminium pan,

- latent heat of vapourization,

<u>Using the equation of heat:</u>
<em>Here, initially certain mass of water is vapourised first and then the remaining mass of water comes in thermal equilibrium with the pan.</em>


