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alexandr402 [8]

2 years ago

8

A sample of an unknown substance has a mass of 0. 158 kg. If 2,510. 0 J of heat is required to heat the substance from 32. 0Â°C

to 61. 0Â°C, what is the specific heat of the substance? Use q equals m C subscript p Delta T. 0. 171 J/(giÂ°C) 0. 548 J/(giÂ°C) 15. 9 J/(giÂ°C) 86. 6 J/(giÂ°C).

1 answer:

guapka [62]2 years ago

4 0

The specific heat of the unknown substance with a mass of 0.158kg is 0.5478 J/g°C

HOW TO CALCULATE SPECIFIC HEAT CAPACITY:

The specific heat capacity of a substance can be calculated using the following formula:

Q = m × c × ∆T

Where;

Q = quantity of heat absorbed (J)
c = specific heat capacity (4.18 J/g°C)
m = mass of substance
∆T = change in temperature (°C)

According to this question, 2,510.0 J of heat is required to heat the 0.158kg substance from 32.0°C to 61.0°C. The specific heat capacity can be calculated:

2510 = 158 × c × (61°C - 32°C)

2510 = 4582c

c = 2510 ÷ 4582

c = 0.5478 J/g°C

Therefore, the specific heat capacity of the unknown substance that has a mass of 0.158 kg is 0.5478 J/g°C.

Learn more about specific heat capacity at: brainly.com/question/2530523

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<u>Densidad</u>

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