1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alexandr402 [8]
3 years ago
8

A sample of an unknown substance has a mass of 0. 158 kg. If 2,510. 0 J of heat is required to heat the substance from 32. 0°C

to 61. 0°C, what is the specific heat of the substance? Use q equals m C subscript p Delta T. 0. 171 J/(gi°C) 0. 548 J/(gi°C) 15. 9 J/(gi°C) 86. 6 J/(gi°C).
Physics
1 answer:
guapka [62]3 years ago
4 0

The specific heat of the unknown substance with a mass of 0.158kg is 0.5478 J/g°C

HOW TO CALCULATE SPECIFIC HEAT CAPACITY:

The specific heat capacity of a substance can be calculated using the following formula:

Q = m × c × ∆T

Where;

  • Q = quantity of heat absorbed (J)
  • c = specific heat capacity (4.18 J/g°C)
  • m = mass of substance
  • ∆T = change in temperature (°C)

According to this question, 2,510.0 J of heat is required to heat the 0.158kg substance from 32.0°C to 61.0°C. The specific heat capacity can be calculated:

2510 = 158 × c × (61°C - 32°C)

2510 = 4582c

c = 2510 ÷ 4582

c = 0.5478 J/g°C

Therefore, the specific heat capacity of the unknown substance that has a mass of 0.158 kg is 0.5478 J/g°C.

Learn more about specific heat capacity at: brainly.com/question/2530523

You might be interested in
During a demonstration of the gravitational force on falling objects to her class, Sarah drops an 11 lb. bowling ball from the t
tia_tia [17]

1.A) 4.9 m  

AL2006 Ace

The instant it was dropped, the ball had zero speed.


After falling for 1 second, its speed was 9.8 m/s straight down (gravity).


Its AVERAGE speed for that 1 second was (1/2) (0 + 9.8) = 4.9 m/s.


Falling for 1 second at an average speed of 4.9 m/s, is covered 4.9 meters.


ANYTHING you drop does that, if air resistance doesn't hold it back.


Read more on Brainly.com - brainly.com/question/11776597#readmore

2 idk sorry

5 0
3 years ago
Read 2 more answers
Two parallel plates of area 2.34*10-3 M2 have 7.07*10-7C of charge placed on them. A6.62*10-5C charge q1 is placed between the p
ira [324]

Answer:

The force exerted on the q_1 is  F =  2.25*10^{3} \ N

Explanation:

From the question we are told that

     The area is  A =  2.34*10^{-3} \ m^2

     The magnitude of charge placed on them is  q =  7.07 * 10^{-7} C

     The charge placed between the plate is q_1 = 6.62 *10^{-5} C

   

The electric field generated around the plate  is mathematically represented as

           E =  \frac{q}{A \epsilon_o}

Substituting values

          E =  \frac{7.07*10^{-7}}{2.34*10^{-3} * 8.85 *10^{-12}}

         E = 34*10^{6} \ V/m

The force exerted the charge q_1 is  mathematically represented as

        F =  q_1 * E

Substituting values  

        F =  6.62 *10^{-5} * 34*10^{6}

        F =  2.25*10^{3} \ N

8 0
3 years ago
Once again, move the balloon to the right and let it go. Note how fast the balloon moves. Next, brush the balloon against the en
lilavasa [31]

Answer:

Yes. The balloon moves faster when it has more electrons and the sweater has fewer electrons

Explanation:

From Plato. Hope this helps!

8 0
3 years ago
Read 2 more answers
The capacitance of a fully-charged capacitor is 11 F. Determine the capacitor's capacitance when it is half charged.
Tcecarenko [31]

Answer:

The capacitance is 11 F for half and fully charged capacitor.

Explanation:

Capacitance of capacitor is given by the expression

             C=\frac{\epsilon A}{d}

Where ε is the  vacuum permittivity, A is the area of plates and d is the separation between plates.

So capacitance does not depend upon charge and potential. So capacitance fully and half charged capacitors are same.

Here the capacitance is 11 F for half and fully charged capacitor.

4 0
3 years ago
Write a hypothesis for Part II of the lab, which is about the relationship described by F = ma. In the lab, you will use a toy c
Tanzania [10]
If you increase the mass m of the car, the force F will increase, while acceleration a is kept constant. Because F and m are directly proportional.
If you increase the acceleration a of the car, the force F will increase, while mass m is kept constant. Because F and a are directly proportional.

How can Newton's laws be verified experimentally; is by setting this experiment, and changing one variable while keeping the other constant, then observe the change in F.

Hope this helps.
5 0
3 years ago
Read 2 more answers
Other questions:
  • Dalvin pushed a 20kg obiect a distance of 10 meters in 30 seconds. He pushed a 40kg object a distance of 5 meters in 30 seconds.
    14·1 answer
  • Which physical property is used to identify matter based on solubility
    10·1 answer
  • Can a body be in equilibrium if only one external force act on its ? explain
    15·1 answer
  • Ten students stand in a circle and are told to make a transverse wave. what best describes the motion of the students?
    6·2 answers
  • With a doctor’s permission, how many servings of the product could a person eat before reaching 100 percent of their allowable d
    13·1 answer
  • Does the temperature of the water change the fluid pressure in the water?
    5·1 answer
  • A sensitive gravimeter at a mountain observatory finds that the free-fall acceleration is 0.0055 m/s2 less than that at sea leve
    9·1 answer
  • Which of the following involves an endothermic reaction?
    12·2 answers
  • Anya is observing an organism in the laboratory. The table below shows her observations. *
    10·1 answer
  • When forklift moves a crate, it performs _______.
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!