Answer:
We can't see the options so we don't know what we can put
Explanation:
Answer:
1s22s22p6<u>3s23p4</u>
Explanation:
Sulfur is located in the p block and has 6 valence electrons (the 2 exponent on the 3s and the 4 exponent on the 3p add up to 6)
The equation is:
3 O₂ + 4 Co → 2 Co₂O₃
Oxidation half reaction:
Co → Co³⁺ + 3 e
Reduction half reaction:
O₂ + 4 e → 2 O²⁻
To balance the equation number of electrons lost must be equal to number or electrons gained so we must multiply oxidation half time 4 and reduction half times 3
Salt dissolving in a glass of water, using electricity to break down water into hydrogen and oxygen, rust forming on an iron fence and gas burning on a stove.
<u>Answer:</u> The solubility of
in water is ![1.18\times 10^{-7}mol/L](https://tex.z-dn.net/?f=1.18%5Ctimes%2010%5E%7B-7%7Dmol%2FL)
<u>Explanation:</u>
The balanced equilibrium reaction for the ionization of cadmium phosphate follows:
![Cd_3(PO_4)_2\rightleftharpoons 3Cd^{2+}+2PO_4^{3-}](https://tex.z-dn.net/?f=Cd_3%28PO_4%29_2%5Crightleftharpoons%203Cd%5E%7B2%2B%7D%2B2PO_4%5E%7B3-%7D)
3s 2s
The expression for solubility constant for this reaction will be:
![K_{sp}=[Cd^{2+}]^3[PO_4^{3-}]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BCd%5E%7B2%2B%7D%5D%5E3%5BPO_4%5E%7B3-%7D%5D%5E2)
We are given:
![K_{sp}=2.5\times 10^{-33}](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D2.5%5Ctimes%2010%5E%7B-33%7D)
Putting values in above equation, we get:
![2.5\times 10^{-33}=(3s)^3\times (2s)^2\\\\2.5\times 10^{-33}=108s^5\\\\s=1.18\times 10^{-7}mol/L](https://tex.z-dn.net/?f=2.5%5Ctimes%2010%5E%7B-33%7D%3D%283s%29%5E3%5Ctimes%20%282s%29%5E2%5C%5C%5C%5C2.5%5Ctimes%2010%5E%7B-33%7D%3D108s%5E5%5C%5C%5C%5Cs%3D1.18%5Ctimes%2010%5E%7B-7%7Dmol%2FL)
Hence, the solubility of
in water is ![1.18\times 10^{-7}mol/L](https://tex.z-dn.net/?f=1.18%5Ctimes%2010%5E%7B-7%7Dmol%2FL)