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maw [93]
2 years ago
5

Pre-Algebra and Physical Science

Physics
2 answers:
Irina18 [472]2 years ago
6 0
Yeah! Your question?
PolarNik [594]2 years ago
4 0

Answer:

Hey pal what is the question

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A man pushed the box with a force of 20 N. He doubled his force to 40 N. The box did not
Alex787 [66]

Answer:

A

Explanation:

if the man doubles his force to 40 and the box was yet to move that means acceleration also doubled so your answer would be A

8 0
3 years ago
Why does a stop sign appear red?
dolphi86 [110]

Answer:

because it’s suppose to be red like a stop light.

Explanation:

So it tells you to stop

8 0
3 years ago
If 90 grams of gold has a volume of 5 cm3, calculate the density (include the units and show your work or you get no credit
ehidna [41]

Answer:

The density of gold is of 18 grams per cm3.

Explanation:

The mass density of a homogeneous material expresses how much mass of that material is present in a given volume. Since the density of an object is obtained by dividing its mass by its volume, to obtain the density of gold, its 90 grams of mass must be divided by its 5 cm3 volume, performing the following calculation:

90/5 = X

18 = X

Thus, the density of gold is 18 grams per cm3.

6 0
3 years ago
Whats the answer???????????
Leviafan [203]

Answer: Less than 4 ohms

Explanation:

We have three resistors with the following resistance:

R_{1}=4\Omega

R_{2}=6\Omega

R_{3}=8\Omega

Now, when the resistors are connected in parallel, the total resistance R is calculated as follows:

\frac{1}{R}=\frac{1}{R_{1}}+\frac{1}{R_{2}}+\frac{1}{R_{3}}

Isolating R:

R=\frac{R_{1}R_{2}R_{3}}{R_{3}(R_{1}+R_{2})+R_{1}R_{2}}

Rewriting with th known values:

R=\frac{(4\Omega)(6\Omega)(8\Omega)}{8\Omega(4\Omega+6\Omega)+(4\Omega)(6\Omega)}

Finally:

R=1.84 \Omega

Hence, the correct option is less than 4 ohms.

4 0
3 years ago
When you speak, your voice is produced by your vibrating vocal chords. These vibrations produce the ________ which carry _______
Len [333]
Produce waves that carry sound
7 0
3 years ago
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