Answer: 2:2 but if simplified it’s 1:1
Explanation:
This is a straightforward dilution calculation that can be done using the equation
where <em>M</em>₁ and <em>M</em>₂ are the initial and final (or undiluted and diluted) molar concentrations of the solution, respectively, and <em>V</em>₁ and <em>V</em>₂ are the initial and final (or undiluted and diluted) volumes of the solution, respectively.
Here, we have the initial concentration (<em>M</em>₁) and the initial (<em>V</em>₁) and final (<em>V</em>₂) volumes, and we want to find the final concentration (<em>M</em>₂), or the concentration of the solution after dilution. So, we can rearrange our equation to solve for <em>M</em>₂:

Substituting in our values, we get
![\[M_2=\frac{\left ( 50 \text{ mL} \right )\left ( 0.235 \text{ M} \right )}{\left ( 200.0 \text{ mL} \right )}= 0.05875 \text{ M}\].](https://tex.z-dn.net/?f=%5C%5BM_2%3D%5Cfrac%7B%5Cleft%20%28%2050%20%5Ctext%7B%20mL%7D%20%5Cright%20%29%5Cleft%20%28%200.235%20%5Ctext%7B%20M%7D%20%5Cright%20%29%7D%7B%5Cleft%20%28%20200.0%20%5Ctext%7B%20mL%7D%20%5Cright%20%29%7D%3D%200.05875%20%5Ctext%7B%20M%7D%5C%5D.)
So the concentration of the diluted solution is 0.05875 M. You can round that value if necessary according to the appropriate number of sig figs. Note that we don't have to convert our volumes from mL to L since their conversion factors would cancel out anyway; what's important is the ratio of the volumes, which would be the same whether they're presented in milliliters or liters.
c.Both the breaking of nuclear bonds and the forming of nuclear bonds.
Explanation:
Nuclear energy is released by the breaking and forming of nuclear bonds. The breaking of nuclear bonds by unstable atoms is known as nuclear fission. The forming of nuclear bonds by combination of light atoms is known as nuclear fusion.
- Nuclear fission is a radioactive decay process in which a heavy nucleus spontaneously disintegrates into lighter ones with the release of energy.
- In nuclear fusion, atomic nuclei combines into larger ones with the release of large amount of energy.
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Molecular orbital energy is the energy associated with each electron in an atom or molecule.
It is expressed in electron volts (eV) and is determined by the electron's position in the atom or molecule. The molecular orbital energy diagram and fill-in the electrons are given here in each case, the number of valence electrons in the species is determined first; this is followed by the valence molecular orbital diagram for each species.
C2+: Molecular Orbital Energy Diagram
1s2 2s2 2p2
σ2s* ← 0 e-
σ2s ← 2 e-
σ2p* ← 0 e-
σ2p ← 0 e-
π2p* ← 0 e-
π2p ← 0 e-
Bond Order: 0
Stability: Unstable
Magnetism: Diamagnetic (no unpaired electrons)
O2-: Molecular Orbital Energy Diagram
1s2 2s2 2p4
σ2s* ← 0 e-
σ2s ← 2 e-
σ2p* ← 0 e-
σ2p ← 2 e-
π2p* ← 0 e-
π2p ← 2 e-
Bond Order: 1
Stability: Stable
Magnetism: Paramagnetic (2 unpaired electrons)
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C i think i got this off of usa test prep in class