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3 years ago

A book is pushed off the edge of a table. At what point during the fall will the potential and kinetic energy be equal?

Chemistry

1 answer:

vfiekz [6]3 years ago

5 0

Answer:

KE = PE at half the table Height:

Explanation

AT ANY POINT IN THE BOOK'S FALL,

TOTAL E = PE +KE

THE TOTAL E IS CONSTANT

Before the book is pushed off, the total energy is potential

TOT E=PE =MGH

BEFORE THE BOOK HITS THE GROUND, THE TOTAL E IS KINETIC

TOT=KE = MVXV/2

WHEN KE = PE

KE+PE = MGH (STARTING ENERGY SINCE E IS CONSERVED)

OR PE+ PE = MGH

OR MGH' + MGH' =MGH

OR 2H' =H

H' (NEW HEIGHT) =H/2

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3 years ago

Read 2 more answers

C + O2 = CO2

geniusboy [140]

Answer:

44 grams of CO₂ will be formed.

Explanation:

The balanced reaction is:

C + O₂ → CO₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

C: 1 mole
O₂: 1 mole
CO₂: 1 mole

Being the molar mass of each compound:

C: 12 g/mole
O₂: 32 g/mole
CO₂: 44 g/mole

By stoichiometry the following mass quantities participate in the reaction:

C: 1 mole* 12 g/mole= 12 g
O₂: 1 mole* 32 g/mole= 32 g
CO₂: 1 mole* 44 g/mole= 44 g

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

If 12 grams of C react, by stoichiometry 32 grams of O₂ react. But you have 40 grams of O₂. Since more mass of O₂ is available than is necessary to react with 12 grams of C, carbon C is the limiting reagent.

Then by stoichiometry of the reaction, you can see that 12 grams of C form 44 grams of CO₂.

44 grams of CO₂ will be formed.

3 0

3 years ago

if 334.6 g of phosphoric acid is reacted with excess potassium hydroxide. the final mass K3PO4 produced is found to be 248g. wha

Orlov [11]

Answer:

%age Yield = 34.21 %

Explanation:

The balance chemical equation for the decomposition of KClO₃ is as follow;

3 KOH + H₃PO₄ → K₃PO₄ + 3 H₂O

Step 1: Calculate moles of H₃PO₄ as;

Moles = Mass / M/Mass

Moles = 334.6 g / 97.99 g/mol

Moles = 3.414 moles

Step 2: Find moles of K₃PO₄ as;

According to equation,

1 moles of H₃PO₄ produces = 1 moles of K₃PO₄

So,

3.414 moles of H₃PO₄ will produce = X moles of K₃PO₄

Solving for X,

X = 1 mol × 3.414 mol / 1 mol

X = 3.414 mol of K₃PO₄

Step 3: Calculate Theoretical yield of K₃PO₄ as,

Mass = Moles × M.Mass

Mass = 3.414 mol × 212.26 g/mol

Mass = 724.79 g of K₃PO₄

Also,

%age Yield = Actual Yield / Theoretical Yield × 100

%age Yield = 248 g / 724.79 × 100

%age Yield = 34.21 %

3 0

3 years ago

what is the balanced equation when copper metal is placed in a solution when platnium ii chloride is placed. what is the equatio

koban [17]

Answer:

$Cu~+~PtCl_2->Pt~+~CuCl_2$

Explanation:

In this case, we can start with the formula of Platinum (II) Chloride. The cation is the atom at the left of the name (in this case $Pt^+^2$ ) and the anion is the atom at the right of the name (in this case $Cl^-$ ). With this in mind, the formula would be $PtCl_2$ .