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tatuchka [14]
3 years ago
5

Standardization is the process of titrating a solution prepared from

Chemistry
1 answer:
Zolol [24]3 years ago
6 0

Answer:

Standardization is the process of titrating a solution prepared from a carefully measured mass of solid accurately determine the concentration of the titrant.

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A saturated solution of potassium chlorate is dissolved in 100g of water. If the saturated solution is cooled from 90 degrees Ce
dedylja [7]

Mass would crystallize out : 24 g

<h3>Further explanation </h3>

Solubility is the maximum amount of a substance that can dissolve in some solvents. Factors that affect solubility

  • 1. Temperature:
  • 2. Surface area:
  • 3. Solvent type:
  • 4. Stirring process:

We can use solubility graph to solve this.

solubility KClO₃ at 90°C=52 g

solubilty KCl₃ at 60°C= 28 g

Mass would crystallize out = 52 - 28 =24 g

4 0
3 years ago
Sort each characteristic according to whether it describes acid, bases, or both.
VARVARA [1.3K]

Answer:

Acids: react with metals, taste sour

Both: can cause burns, conduct electricity

Basis: react with nonmetals, taste bitter

Explanation:

This is the right answer

4 0
3 years ago
10. For each of the following pairs of ionic compounds, state which would be expected to have the higher (more negative) lattice
zaharov [31]

Answer:

C I belive

Explanation:

7 0
3 years ago
Which of the following compounds has the highest boiling point?
marta [7]
The answer is chloropentane

3 0
4 years ago
Read 2 more answers
A gas system has an unknown pressure and an initial temperature of 299K. When the temperature is increased to 620 K the pressure
const2013 [10]

Answer:

3.75 atm

Explanation:

Volume remains constant, so we can use <em>Gay-Lussac’s Law</em>.

<em>p</em>₁/<em>T</em>₁ = <em>p</em>₂/<em>T</em>₂                           Multiply both sides by <em>T</em>₁  

<em>p</em>₁ = <em>p</em>₂ × <em>T</em>₁/<em>T</em>₂

<em>p</em>₁ = ?;              <em>T</em>₁ = 299 K

<em>p</em>₂ = 7.77 atm; <em>T</em>₂ = 620 K     Insert the values

<em>p</em>₁ = 7.77 × 299/620              Do the operations

<em>p</em>₁ = 3.75 atm

3 0
3 years ago
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