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3 years ago

How many valence electrons does a neutral atom of beryllium have

Chemistry

1 answer:

andrezito [222]3 years ago

8 0

Answer:

A neutral Beryllium atom has two (2) valence electrons

Explanation:

<em>Beryllium, Be,</em> is a group 2 element on the periodic table. Its atomic number is 4.

Generally, atomic number equals number of electrons, which means a neutral Beryllium atom contains four (4) electrons: two (2) in the inner shells and 2 in the outer shell (valence electrons), which can take part in a chemical reaction and participate in chemical bonding.

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Elements can be described by various properties, and identified by their boiling and melting points. For example, gold melts at

aleksandr82 [10.1K]

Answer:

Explanation:

Melting and boiling point variations are not clear (do not have uniform pattern) in periodic table. But we can see, some elements have higher melting and boiling points and some have less. Here we study melting and boiling points of s, p, d blocks elements. IVAth group elements (C,Si) show high melting and boiling points because they have covalent gigantic lattice structures.

5 0

2 years ago

Read 2 more answers

How many formula units make up 10.2 g of magnesium chloride (MgCl2)?

beks73 [17]

Answer:

6.46×10²² formula units

Explanation:

From the question given above, the following data were obtained:

Mass of MgCl₂ = 10.2 g

Number of formula units =?

From Avogadro's hypothesis,

1 mole of MgCl₂ = 6.02×10²³ formula units

But,

1 mole of MgCl₂ = 24 + (35.5×2) = 24 + 71 = 95 g

Thus, we can say:

95 g of MgCl₂ = 6.02×10²³ formula units

Finally, we shall determine the formula units in 10.2 g MgCl₂. This can be obtained as follow:

95 g of MgCl₂ = 6.02×10²³ formula units

Therefore,

10.2 g of MgCl₂ = (10.2 × 6.02×10²³) / 95

10.2 g of MgCl₂ = 6.46×10²² formula units

Thus, 10.2 g of MgCl₂ contains 6.46×10²² formula units

6 0

3 years ago

What mass of ag2co3 could you produce from 12.7 g agno3 assuming that it is the limiting reagent?

zhenek [66]

10.3 g of $Ag_{2} CO_{3}$ will produce from 12.7 g $AgNO_{3}$ .

In simple terms, a limiting reagent is a reactant that is completely used up in the reaction.

It is also referred to as a limiting reactant or limiting agent.

Now, according to the question,

Since it is a limiting reagent, it will react fully.

The mass of $AgCO_{3}$ that will be produced will be:-

Equivalent mole of $AgNO_{3}$ = Equivalent weight of $Ag_{2} CO_{3}$ = 12.7/169.97 = x*2/274x = 10.3 g.

Hence, 10.3 g of $Ag_{2} CO_{3}$ will be produced.

It is used to restrict the reaction.

It tells you the estimated amount of compound to be used.

It brings quantitative understanding to chemical reactions.

More information on limiting reagents can be found here :

brainly.com/question/11848702

#SPJ4

7 0

2 years ago

How many atoms are in 1.6g C? Answer in units of atoms. <br><br> (no answer choices were given)

maksim [4K]

Answer:

6.022 ×10(index 23) / 7.5 = 0.8293 ×10(index 23)

Explanation:

molar mass of C = 12gmol

therefore in 12g of C there is one mole or an amount of 6.022 ×10(index 23)

∴12g/6.02210(index 23) ×1.6g

3 0

2 years ago

What is the theoretical yield of aspirin ( C 9 H 8 O 4 ), which has a molar mass of 180.15 g/mol, possible when reacting 3.03 g

pantera1 [17]

Answer:

The theoretical yield of aspirin is 3.95 grams

Explanation:

Step 1: Data given

Mass of salicylic acid = 3.03 grams

Volume of acetic anhydride = 3.61 mL

Density of acetic anhydride = 1.08 g/cm³

Step 2: The balanced equation

C4H6O3+C7H6O3→C9H8O4+C2H4O2

Step 3: Calculate moles salicylic acid

Moles salicylic acid = mass salicylic acid / molar mass salicylic acid

Moles salicylic acid = 3.03 grams /138.121 g/mol

Moles salicylic acid = 0.0219 moles

Step 4: Calculate mass acetic anhydride

Mass acetic anhydride = volume * density

Mass acetic anhydride = 3.61 mL * 1.08 g/mL

Mass acetic anhydride = 3.90 grams

Step 5: Calculate moles acetic anhydride

Moles acetic anhydride = 3.90 grams / 102.09 g/mol

Moles acetic anhydride = 0.0382 moles

Step 6: Calculate limiting reactant

For 1 mol salicylic acid we need 1 mol acetic anhydride to produce 1 mol aspirin

Salicylic acid is the limiting reactant. It will completely be consumed. (0.0219 moles). Acetic anhydride is in excess. There will react 0.0219 moles. There remain 0.0382 - 0.0219 =0.0163 moles

Step 7: Calculate moles aspirin

For 1 mol salicylic acid we need 1 mol acetic anhydride to produce 1 mol aspirin

For 0.0219 moles salicylic acid we'll have 0.0219 moles aspirin

Step 8: Calculate theoretical yield of aspirin

Mass of aspirin = moles aspirin *molar mass aspirin

Mass of aspirin = 0.0219 moles *180.15 g/mol

Mass of aspirin = 3.95 grams

The theoretical yield of aspirin is 3.95 grams

7 0

3 years ago