Which was an idea used to promote the theory of plate tectonics

At t1 = 2.00 s, the acceleration of a particle in counterclockwise circular motion is 6.00 i + 4.00 j m/s2 . It moves at constan

Jet001 [13]

The particle moves with constant speed in a circular path, so its acceleration vector always points toward the circle's center.

At time $t_1$ , the acceleration vector has direction $\theta_1$ such that

$\tan\theta_1=\dfrac{4.00}{6.00}\implies\theta_1=33.7^\circ$

which indicates the particle is situated at a point on the lower left half of the circle, while at time $t_2$ the acceleration has direction $\theta_2$ such that

$\tan\theta_2=\dfrac{-6.00}{4.00}\implies\theta_2=-56.3^\circ$

which indicates the particle lies on the upper left half of the circle.

Notice that $\theta_1-\theta_2=90^\circ$ . That is, the measure of the major arc between the particle's positions at $t_1$ and $t_2$ is 270 degrees, which means that $t_2-t_1$ is the time it takes for the particle to traverse 3/4 of the circular path, or 3/4 its period.

Recall that

$\|\vec a_{\rm rad}\|=\dfrac{4\pi^2R}{T^2}$

where $R$ is the radius of the circle and $T$ is the period. We have

$t_2-t_1=(5.00-2.00)\,\mathrm s=3.00\,\mathrm s\implies T=\dfrac{3.00\,\rm s}{\frac34}=4.00\,\mathrm s$

and the magnitude of the particle's acceleration toward the center of the circle is

$\|\vec a_{\rm rad}\|=\sqrt{\left(6.00\dfrac{\rm m}{\mathrm s^2}\right)^2+\left(4.00\dfrac{\rm m}{\mathrm s^2}\right)^2}=7.21\dfrac{\rm m}{\mathrm s^2}$

So we find that the path has a radius $R$ of

$7.21\dfrac{\rm m}{\mathrm s^2}=\dfrac{4\pi^2R}{(4.00\,\mathrm s)^2}\implies\boxed{R=2.92\,\mathrm m}$

8 0

3 years ago

Solids that have flat sides and a repeating pattern of atoms are called ______________.

DiKsa [7]

they are called crystals

7 0

4 years ago

Differentiate between:<br><br>a. Compression and Rarefaction<br>

zlopas [31]

Answer:

Explanation:

Compression

The region in a medium where the distance between the vibrating molecules is minimum is compression.

This is the region with higher air pressure than the surrounding .

Rarefaction

The region in a medium where the distance between the vibrating molecules is maximum is rarefaction.

This is the region with relatively low air pressure.

hope it helps :)

7 0

3 years ago

THIS IS DUE IN 5 MINUTES IM BEGGING YOU PLEASE ANSWER

Archy [21]

Answer:

the answer is A or 900

Explanation:

what u have to do is add all the forces together and then u get ur answer.

4 0

3 years ago

Help me out please. It’d be greatly appreciated

ludmilkaskok [199]

Answer:

Option D

2Na + Cl₂ —> 2NaCl

Explanation:

We'll begin by stating the law of conservation of matter.

The law of conservation of matter states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.

For an equation to comply with the law of conservation of matter, the number of atoms of each element must be the same on both side of the equation. This simply means that the equation must be balanced!

NOTE: An unbalanced equation simply means matter has been created or destroyed.

Now, we shall determine which equation is balanced. This can be obtained as follow:

For Option A

Na + Cl₂ —> 2NaCl

Reactant:

Na = 1

Cl = 2

Product:

Na = 2

Cl = 2

Thus, the equation is not balanced!

For Option B

2Na + 2Cl₂ —> 2NaCl

Reactant:

Na = 2

Cl = 4

Product:

Na = 2

Cl = 2

Thus, the equation is not balanced!

For Option C

2Na + Cl₂ —> NaCl

Reactant:

Na = 2

Cl = 2

Product:

Na = 1

Cl = 1

Thus, the equation is not balanced!

For Option D

2Na + Cl₂ —> 2NaCl

Reactant:

Na = 2

Cl = 2

Product:

Na = 2

Cl = 2

Thus, the equation is balanced!

From the above illustrations, only option D has a balanced equation. Thus, option D illustrate the law of conservation of matter.

5 0

3 years ago