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3 years ago

- Complete the chart. What does "charge” mean in this passage?

Physics

1 answer:

Maslowich3 years ago

3 0

Answer:

demand (an amount) as a price from someone for a service rendered or goods supplied.

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Two engineering students, John with a weight of 96 kg and Mary with a weight of 48 kg, are 30 m apart. Suppose each has a 0.04%

djyliett [7]

Answer:

$6.8370869499\times 10^{20}\ N$

Explanation:

$N_A$ = Avogadro's number = $6.022\times 10^{23}$

e = Charge of electron = $1.6\times 10^{-19}\ C$

k = Coulomb constant = $8.99\times 10^{9}\ Nm^2/C^2$

Z = Atomic number of water = 18

M = Molar mass of water = 0.018 kg/mol

m = Mass of person

The charge is given by

$q=imbalance\times n\times e$

Total number of protons and electrons in each sphere

$n=\dfrac{mN_AZe}{M}$

$q=imbalance\times \dfrac{mN_AZe}{M}$

$q_1=0.0004\times \dfrac{96\times 6.022\times 10^{23}\times 18\times 1.6\times 10^{-19}}{0.018}\\\Rightarrow q_1=3699916.8\ C$

$q_2=0.0004\times \dfrac{48\times 6.022\times 10^{23}\times 18\times 1.6\times 10^{-19}}{0.018}\\\Rightarrow q_1=1849958.4\ C$

Electrical force is given by

$F=\dfrac{kq_1q_2}{r^2}\\\Rightarrow F=\dfrac{8.99\times 10^{9}\times 3699916.8\times 1849958.4}{30^2}\\\Rightarrow F=6.8370869499\times 10^{20}\ N$

The electrostatic force of attraction between them is $6.8370869499\times 10^{20}\ N$

4 0

4 years ago

Why do scientist use different types of models to represent compounds

nexus9112 [7]

Because they are different they all show different traits.

5 0

3 years ago

If you push a chair across the floor at a constant velocity, how does the force of friction compare with the force you exert? ex

patriot [66]

If the velocity of the chair is constant, then the net force acting on it is zero.

The force you exert to keep it going is equal and opposite to the force of friction.

6 0

3 years ago

At 600.0 k the rate constant is 6.1× 10–8 s–1. what is the value of the rate constant at 785.0 k?

photoshop1234 [79]

Missing details. Complete text is:"The following reaction has an activation energy of 262 kJ/mol:
C4H8(g) --> 2C2h4(g)
At 600.0 K the rate constant is 6.1× 10–8 s–1. What is the value of the rate constant at 785.0 K?"
To solve the exercise, we can use Arrhenius equation:
$\ln( \frac{K_2}{K_1} ) = \frac{Ea}{R} ( \frac{1}{T_1}- \frac{1}{T_2} )$
where K are the reaction rates, Ea is the activation energy, R=8.314 J/mol*K and T are the temperatures. Using T1=600 K and T2=785 K, and Ea=262 kJ/mol = 262000 J/mol, on the right side of the equation we have
$\frac{Ea}{R}( \frac{1}{T_1}- \frac{1}{T_2} )=12.38$
And so
$\ln( \frac{K_2}{K_1})=12.38$
And using $K_1=6.1\cdot 10^{-8} s^{-1}$ , we find K2:
$K_2=K_1 e^{12.38}=0.0145 s^{-1}$

5 0

3 years ago

Explain what is happening when the girl is at each point. **The girl has started at 1 and goes to 4.

Shkiper50 [21]

Gravity
Is happening

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3 years ago