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ra1l [238]
3 years ago
11

What is the Molarity of a Ca(OH)2 solution if 30.0mL of the solution is neutralized by 26.4mL of 0.25M HCI

Chemistry
1 answer:
ale4655 [162]3 years ago
3 0

Answer:

0.11M

Explanation:

What is the Molarity of a Ca(OH)2 solution if 30.0mL of

the solution is neutralized by 26.4mL of 0.25M HCI solution?

1L (1000 ml) of the HCl contains 0.25 moles of H ion

26.4 ml contains ( 26.4 X0.25/1000) moles of H ion ion

=0.0066 moles H ion

2HCl +Ca (OH)2-----> 2H2O +CaCl2

SO 2 H IONS NEUTRALIZE 1 Ca(OH)2 MOLECULE

00066 moles H ion neutralize 0.0033 moles Ca(OH)2

the 0.0033 moles are distributed over 30 ml, so the concentration of the

Ca(OH)2 IS 0,0033/(30/1000) =0.11 moles/liter or 0.11M

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Answer 1:
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The cell representation of above reaction is given by;
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Answer 2: 
Consider reaction: <span>Pb^2+ (aq) +H2 (g) ----> Pb (s) +2H^+ (aq)
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The cell representation of above reaction is given by;
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Hence, E^{0}cell = E^{0} Pb/Pb^{2+} - E^{0} H_{2}/H^{+}
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Since,  E^{0} cell is negative, hence cell reaction is non-spontaneous.

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Answer 3: 
Consider reaction: <span>2Ag^+ (aq) + Cr(s) ---> 2 Ag (s) +Cr^2+ (aq)
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The cell representation of above reaction is given by;
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