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Sav [38]
3 years ago
6

Scientists plan to release a space probe that will enter the atmosphere of a gaseous planet. The temperature of the gaseous plan

et increases linearly with the height of the atmosphere as measured from the top of a visible boundary layer, defined as 0 kilometers in altitude. The instruments on board can withstand a temperature of 601 K. At what altitude will the probe's instruments fail? A. 50 kilometers B. 80 kilometers C. 83 kilometers D. 100 kilometers E. 111 kilometers
Physics
1 answer:
Elan Coil [88]3 years ago
8 0

Answer:

Scientists plan to release a space probe that will enter the atmosphere of a gaseous planet. The temperature of the gaseous planet increases linearly with the height of the atmosphere as measured from the top of a visible boundary layer, defined as 0 kilometers in altitude. The instruments on board can withstand a temperature of 601 K. At what altitude will the probe's instruments fail? A. 50 kilometers B. 80 kilometers C. 83 kilometers D. 100 kilometers E. 111 kilometers

Explanation:

A. 50 kilometers

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Diano4ka-milaya [45]
The answer would be B.

6 0
3 years ago
A 120-kg object and a 420-kg object are separated by 3.00 m At what position (other than an infinitely remote one) can the 51.0-
djverab [1.8K]

Answer:

1.045 m from 120 kg

Explanation:

m1 = 120 kg

m2 = 420 kg

m = 51 kg

d = 3 m

Let m is placed at a distance y from 120 kg so that the net force on 51 kg is zero.

By use of the gravitational force

Force on m due to m1 is equal to the force on m due to m2.

\frac{Gm_{1}m}{y^{2}}=\frac{Gm_{2}m}{\left ( d-y \right )^{2}}

\frac{m_{1}}{y^{2}}=\frac{m_{2}}{\left ( d-y \right )^{2}}

\frac{3-y}{y}=\sqrt{\frac{7}{2}}

3 - y = 1.87 y

3 = 2.87 y

y = 1.045 m

Thus, the net force on 51 kg is zero if it is placed at a distance of 1.045 m from 120 kg.

6 0
4 years ago
Airbags and safety belts can reduce injuries because they can
pashok25 [27]

Answer:

reduce the velocity of collision

5 0
3 years ago
Warm air aloft is normally higher pressure relative to colder air aloft, which is normally of lower pressure (at equivalent alti
Allisa [31]

Answer:

the statement given is False.

Explanation:

The pressure is defined by

     P = F / A

The force of the air is its weight,

     P = W_air / A

The weight of an air column on us depends on the energy of the molecules that is related to the temperature

      E = 3/2 K T

 When the air is warmer it has more energy so the molecules can move more distance and therefore the average density of the gas decreases, as the density decreases, the weight of the column on us also decreases, therefore the pressure low.

The correct statement is: When the air is hotter it has less pressure than when the air is cold.

 It is summary the statement given is False

6 0
4 years ago
I need help ASAP....
Svetradugi [14.3K]

Answer:

Meters

Explanation:"How FAR did the athlete run?"

Also it talked about meters

5 0
4 years ago
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