Answer:
1.045 m from 120 kg
Explanation:
m1 = 120 kg
m2 = 420 kg
m = 51 kg
d = 3 m
Let m is placed at a distance y from 120 kg so that the net force on 51 kg is zero.
By use of the gravitational force
Force on m due to m1 is equal to the force on m due to m2.



3 - y = 1.87 y
3 = 2.87 y
y = 1.045 m
Thus, the net force on 51 kg is zero if it is placed at a distance of 1.045 m from 120 kg.
Answer:
reduce the velocity of collision
Answer:
the statement given is False.
Explanation:
The pressure is defined by
P = F / A
The force of the air is its weight,
P = W_air / A
The weight of an air column on us depends on the energy of the molecules that is related to the temperature
E = 3/2 K T
When the air is warmer it has more energy so the molecules can move more distance and therefore the average density of the gas decreases, as the density decreases, the weight of the column on us also decreases, therefore the pressure low.
The correct statement is: When the air is hotter it has less pressure than when the air is cold.
It is summary the statement given is False
Answer:
Meters
Explanation:"How FAR did the athlete run?"
Also it talked about meters