I’m not sure just need to answer questions to help me so sorry
One solution to your problem is 15(1-2x)
We are going to round the number '3'.
Look at the first number to the right of '3', which is '9'.
That number is greater than '5', so you round the '3' to '4', and add three zeros after '4'.
Answer is: 4,000
Answer:
The nth term in the sequence is given by the equation:

Step-by-step explanation:
Arranging a table for n and nth:
![\left[\begin{array}{ccc}n&nth\\1&1\\2&3\\2&16\\4&125\\5&1296\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dn%26nth%5C%5C1%261%5C%5C2%263%5C%5C2%2616%5C%5C4%26125%5C%5C5%261296%5Cend%7Barray%7D%5Cright%5D)
It is easier to notice that 16 and 125 result from the second power of 4 and the third of 5, respectively, which are one number below their respective position. That is why we can deduce that the base of the power is n+1.
For n=2, the base n+1 results in 3, which matches the nth term for n=2. Since 3 is the result of 3 to the power of 1, 16 is 4 to the power of 2, and 125 is 5 to the power of 3, all the powers are one number behind n, so the power is given by n-1, giving the equation:
