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3 years ago

The standard metric unit of volume is the _____.

Physics

1 answer:

Nataliya [291]3 years ago

4 0

Answer:

. The SI unit of volume is the cubic meter (m3), which is a derived unit.

Liter (L) is a special name for the cubic decimeter (dm3).

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Two forces act at a point in the plane. The angle between the two forces is given. Find the magnitude of the resultant force. fo

Zielflug [23.3K]

Answer:

408N at 89.89°

Explanation:

This problem requires that we resolve the force vectors into

x- and y

-componentsOnce this is done, we can add the components easily, as the one 2-dimensional problem will be two 1-dimensional problems.

Finally, we will convert the resultant force into standard form and find the equilibrant.

Resolve into components:

F1x =F1cos 180°= 232(−1)=−232N

F1y=F1sin180°=0N

F2x=F2cos(−140°)=194(−0.766)=−148.6N

F1y=F1sin(−140°)=232(−0.643)=−149.17N

Note the change of the angle used to give the direction of

F2. Standard angles (rotation from thex

-axis; counterclockwise is +) should be used to avoid sign errors in the results.

Now, we add the components:

Fx=F1x+F2x=−380.6N

Fy=F1y+F1y=−148.17N

Technically, this is the resultant force. However, it should be changed back into standard form. Here's how:

F=√(Fx)2(Fy)2=√(−380.6)^2(−148.17)^2=408N

θ=tan−1(−148.17−380.6)

=89.89°

4 0

3 years ago

How much does the gravitational force of attraction change between two asteroids if the two asteroids drift three times closer t

Katen [24]

Answer:

Increase 9 times

Explanation:

We have Newton formula for attraction force between 2 objects with mass and a distance between them:

$F_G = G\frac{M_1M_2}{R^2}$

where $G =6.67408 \times 10^{-11} m^3/kgs^2$ is the gravitational constant. $M_1, M_2$ is the masses of the 2 objects. and R is the distance between them.

Since the force is inversely proportional to the distance squared, if it is reduced by 3 times, the gravitational force between them would increase by $3^2 = 9$ times

6 0

3 years ago

Three kids are riding on a snow sled traveling horizontally without friction at 19.8 m/s. The masses of Kid A, B, and C are 42.8

Kamila [148]

Answer:

34.6 m/s

Explanation:

From conservation of momentum, the sum of initial and final momentum are equal. Momentum is a product of mass and velocity. Initial mass will be 42.8+31.5+25.9=100.2 kg

Final mass will be 31.5+25.9=57.4 kg

From formula of momentum

M1v1=m2v2

Making v2 the subject of the formula then

$V2=\frac {M1v1}{m2}$

Substitute 100.2 kg for M1, 19.8 m/s fkr v1 and 57.4 kg for m2 then

$V2=\frac {100.2 kg\times 19.8 m/s}{57.4 kg}=34.56376 m/s\approx 34.6 m/s$

4 0

3 years ago

how does spatial pattern of heights illustrate the relationship between temperature density and the rate of vertical pressure ch

Anika [276]

The rate of change of vertical pressure is directly proportional to density and also directly proportional to temperature.

Generally, the relationship between temperature, density and rate of vertical pressure is given as;

$\rho = \frac{PM}{RT}$

$\frac{dP}{dz} = -\rho g\\\\$

where;

ρ is density
T is temperature
dP is rate of change of vertical pressure

Thus, from the formula above, we can conclude the following relationship between temperature, density and the rate of vertical pressure change in spatial pattern of heights.

The rate of change of vertical pressure is directly proportional to density and also directly proportional to temperature.

Learn more here:brainly.com/question/25395377

5 0

3 years ago

Two planets, Dean and Sam, orbit the Sun. They each have with circular orbits, but orbit at different distances from the Sun. De

lyudmila [28]

Answer:

The correct answer is Dean has a period greater than San

Explanation:

Kepler's third law is an application of Newton's second law where the force is the universal force of attraction for circular orbits, where it is obtained.

T² = (4π² / G M) r³

When applying this equation to our case, the planet with a greater orbit must have a greater period.

Consequently Dean must have a period greater than San which has the smallest orbit

The correct answer is Dean has a period greater than San

3 0

3 years ago