Question

How much heat is needed to raise the temperature of a 100.0g of water by 85.0 c?

Answer 1

Answer:

35.7kJ

Explanation:

we can calculate the amount of heat energy required , using this formula

Q = mcθ

where.

Q = heat energy (Joules, J)  

m = mass of a substance (kg)  

c = specific heat capacity (units $Jkg^{-1} C^{-1}$)

θ  = change in temperature (Celcius,C or Kelvin K)

Assume Specific heat capacity (c) of water =$4200Jkg^{-1} C^{-1}$

mass =0.1 kg

$Q=0.1 kg*4200Jkg^{-1} C^{-1}*85C\\=35700J\\=35.7kJ$