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lions [1.4K]
3 years ago
13

Write the full ground state electron configuration of co3+ in abbreviated form

Chemistry
1 answer:
torisob [31]3 years ago
7 0
<span>Co3+ is Cobalt with three electrons removed (It's positive by 3). So, the abbreviated notation for Cobalt, minus three electrons (Coming from 4s and 3d) is: [Ar]4s1, 3d5</span>
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Breaking an object such as a mirror is an example of physical change, chemical change,physical reaction, chemical reaction
dangina [55]

Answer:

option A= Physical change

Explanation:

physical change:

" It is a change in which no new substance is formed"

Breaking of object like glass is the example of physical change because it is not change into another object. It effect the form of object but can not change the chemical composition.

Chemical changes:

" it is a change in which one substance is converted into new product through chemical reaction".

During the chemical changes the types and the number of atom remain same but their arrangement changed.

for example: burning of wood, baking of cake, digesting food, resting of iron etc.

Physical reaction:

" physical reaction occur during the molecular rearrangement. There is no chemical change occur"

In this type of changes no bonds are break to form new bonds, for example boiling point.

Chemical reaction:

" chemical reaction occur when molecules are chemically react with each others and bonds formation and breaking is also occur"

5 0
3 years ago
When 5.00 g of Al2S3 and 2.50 g of H2O are reacted according to the following reaction: Al2S3(s) + 6 H2O(l) → 2 Al(OH)3(s) + 3 H
Debora [2.8K]

Answer:

Y=58.15\%

Explanation:

Hello,

For the given chemical reaction:

Al_2S_3(s) + 6 H_2O(l) \rightarrow 2 Al(OH)_3(s) + 3 H_2S(g)

We first must identify the limiting reactant by computing the reacting moles of Al2S3:

n_{Al_2S_3}=5.00gAl_2S_3*\frac{1molAl_2S_3}{150.158 gAl_2S_3} =0.0333molAl_2S_3

Next, we compute the moles of Al2S3 that are consumed by 2.50 of H2O via the 1:6 mole ratio between them:

n_{Al_2S_3}^{consumed}=2.50gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molAl_2S_3}{6molH_2O}=0.0231mol  Al_2S_3

Thus, we notice that there are more available Al2S3 than consumed, for that reason it is in excess and water is the limiting, therefore, we can compute the theoretical yield of Al(OH)3 via the 2:1 molar ratio between it and Al2S3 with the limiting amount:

m_{Al(OH)_3}=0.0231molAl_2S_3*\frac{2molAl(OH)_3}{1molAl_2S_3}*\frac{78gAl(OH)_3}{1molAl(OH)_3} =3.61gAl(OH)_3

Finally, we compute the percent yield with the obtained 2.10 g:

Y=\frac{2.10g}{3.61g} *100\%\\\\Y=58.15\%

Best regards.

7 0
3 years ago
A sample of polonium-210 has an initial mass of 390 milligrams (mg). If the half-life of polonium-210 is 36 days, how many mg of
kondaur [170]

Answer: D. 48.75

Explanation: just took the test

5 0
3 years ago
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If the gas in the above system has a volume of 256 mL at a pressure
evablogger [386]

Answer:

the volume of the same gas at pressure of 1.00atm =737.3ml

6 0
2 years ago
Molar mass of 4Fe(OH)2
lakkis [162]

Answer: The molar mass and molecular weight of 4Fe is 223.38.

3 0
2 years ago
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