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2 years ago

5

Scores on a standardized test are normally distributed with a mean of 250 and a standard a deviation of 20. Approximately what p

ercent of students scored between 260 and 280? Round to the nearest percent

1 answer:

masha68 [24]2 years ago

5 0

Answer:

You can't answer this properly without more data.

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How you multiply 523x12

Mrac [35]

You multiply 523x12 by writing it out. 523x12 is equal too 6,276

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2 years ago

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Please help me out with this!!!!!!!!!!!!

vesna_86 [32]

Answer:

y = - $\frac{3}{4}$ x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (4, 0) ← 2points on the line

m = $\frac{0-3}{4-0}$ = - $\frac{3}{4}$

Note the line crosses the y- axis at (0, 3 ) ⇒ c = 3

y = - $\frac{3}{4}$ x + 3 ← equation of line

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3 years ago

Is 70 thousand written in a standar for or word form .explain

Kay [80]

Answer:

true

Step-by-step explanation:

because its 70 thousand

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2 years ago

Help please i don’t know how to do it

Norma-Jean [14]

Answer:

Step-by-step explanation:

$\frac{dy}{dx}=x^{2}(y-1)\\\frac{1}{y-1} \text{ } dy=x^{2} \text{ } dx\\\int \frac{1}{y-1} \text{ } dy=\int x^{2} \text{ } dx\\\ln|y-1|=\frac{x^{3}}{3}+C\\$

From the initial condition,

$\ln|3-1|=\frac{0^{3}}{3}+C\\\ln 2=C$

So we have that $\ln |y-1|=\frac{x^{3}}{3}+\ln 2\\e^{\frac{x^{3}}{3}+\ln 2}=y-1\\2e^{\frac{x^{3}}{3}}=y-1\\y=2e^{\frac{x^{3}}{3}}+1$

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2 years ago

Find the common difference of the sequence shown 1/6, 1/4, 1/3

Damm [24]

1/4 - 1/6 = (6-4)/24 = 2/24 = 1/12
1/3 - 1/4 = (4-3)/12 = 1/12

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2 years ago

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