Question

in slope-intercept form, that is perpendicular to the equation =32+6 y = 3 2 x + 6 passing through (-12,15)?

Answer 1

Answer:

Step-by-step explanation:

Is "32+6 y = 3 2 x + 6" written correctly?  I'll assume y=32x+6 is the corerect equation.  If 32+6 y = 3 2 x + 6 is correct, reduce it to:  

6y = 32x-26

y = (16/3)x - 4.5 and follow the same steps

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An equation perpendicular to y=32x+6 will have a slope that is the negative inverse to the reference line slope, in this case 32.  The negative inverse of 32 is -(1/32).

The perpendicular line will be y = -(1/32)x+b.

To find a value for b, use the given point (-12, 15) and solve for b:

y = -(1/32)x+b

15 = -(1/32)*(-12)+b

b = 15- (12/32)

b = 14.625

y=-(1/32)x+14.625