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valentina_108 [34]
1 year ago
8

How many protons, neutrons, and electrons in Cl-?

Chemistry
1 answer:
snow_lady [41]1 year ago
7 0

Answer:

hello . proton:17 electron:18 neutron :18

Explanation:

it's obvious and you must memorise that Cl has 17 protons .

because it has one negative so electrons which are negative should be one more than protons I mean 18

neutron doesn't need to look at it here

electron shows the answer.

hope u understand

if u have any questions don't hesitate to ask.

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The name of CuO is --
Vesnalui [34]

The name is Copper(II) Oxide and/or Cupric Oxide.

Cu is Copper and O is Oxygen.

Usually when the Oxygen ion is placed after another, it's name is Oxide.

6 0
3 years ago
Rewrite the function from vertex form to standard form. Then use either form to calculate f(1) and f(-1).
jonny [76]

Answer:

Standard form: (x+3)^2=1/2(y+3)

f(1) = 29

f(-1) = 5

Explanation:

The standard form of a parabola with a directrix that is horizontal is

(x-h)=4(P)(y-k)

Using the vertex form, find the vertex, foci, and the distance from the vertex to the focus or directrix.

It's easier to use the vertex form to plug in values for x.

f(1) = 2((1)+3)^2-3

f(1) = 29

f(-1) = 2((-1)+3)^2-3

f(-1) = 5

6 0
3 years ago
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Soloha48 [4]
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7 0
3 years ago
When an unknown amine reacts with an unknown acid chloride, an amide with a molecular mass of 163 g/mol (M = 163 m/z) is formed.
DanielleElmas [232]

Answer:

            As the molecular mass of given amine is 163 g/mol (a odd number) it means that this compound contains a odd number of Nitrogen atoms. We will first apply Rule of Thirteen to get the molecular formula.

Rule of Thirteen:

First divide the parent peak value by 13 as,

                = 163 ÷ 13

                = 12.53

Now, multiply 13 by 12,

                = 13 × 12 (here, 12 specifies number of carbon atoms)

                = 156

Now subtract 156 from 163,

                = 163 - 156

                = 7

Add 7 into 12,

                = 7 + 12

                = 19 (hydrogen atoms)

So, the rough formula we have is,

                                                       C₁₂H₁₉

Now, add one Nitrogen atom to above formula and subtract one Carbon and 2 Hydrogen atoms as these numbers are equal to atomic mass of Nitrogen atom as,

                C₁₂H₁₉   -------N-------->    C₁₁H₁₇N

Also, as shown in ¹³C-NMR there is one peak around 180 ppm and the peak at 1661 cm⁻¹ in IR spectrum is characteristic to carbonyl group hence, we will add one oxygen atom to the chemical formula accordingly. i.e.

                C₁₁H₁₇N   -------O-------->    C₁₀H₁₃NO

Molecular Formula: C₁₀H₁₃NO

Also,

In NMR the the four peaks around 120 ppm are assigned to a mono substituted benzene ring.

The absence of IR peak above 3200 cm⁻³ also confirms that the amine is tertiary in nature and there is no hydrogen attached to the nitrogen atom.

It can be observed that the peaks in upfield are duplicating. This can be due to the presence of rotamers of said compound.

The most plausible structure for given data is shown below, and the resonance structure along with rotamers are also shown.

6 0
3 years ago
Write the empirical formula for at least four ionic compounds that could be formed from the following ions:
CaHeK987 [17]

Answer:

Fe(CN)₂,  FeCO₃,  Pb(CN)₄,  Pb(CO₃)₂

Explanation:

Cations (positively charged ions) can only form ionic bonds with anions (negatively charged ions). However, you can't just simply put one cation and one anion together to form a compound. Each compound needs to been neutral, or have an overall charge of 0. When cations and anions do not have charges that perfectly cancel, you need to modify the amount of each ion in the compound.

1.) Fe(CN)₂
-----> Fe²⁺ and CN⁻

-----> +2 + (-1) + (-1) = 0

2.) FeCO₃

-----> Fe²⁺ and CO₃²⁻

-----> +2 + (-2) = 0

3.)  Pb(CN)₄

-----> Pb⁴⁺ and CN⁻

-----> +4 + (-1) + (-1) + (-1) + (-1) = 0

4.) Pb(CO₃)₂

-----> Pb⁴⁺ and CO₃²⁻

-----> +4 +(-2) + (-2) = 0

5 0
2 years ago
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