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2 years ago

Please help me out !!

Chemistry

1 answer:

AfilCa [17]2 years ago

6 0

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Why is it important for someone to hold enzymes in their functional shapes

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Answer:

there are spaces within the enzymes that is active. That active site allows substrates to join in. This helps the enzyme carry out the chemical reaction with the substrate.

Explanation:

4 0

3 years ago

Solve the following problem and round the correct number of significant

RUDIKE [14]

Answer:

4.5 + 2.34 = 6.8

Sig Figs:

Decimals:

Scientific Notation:

6.8 × 10ⁿ

Words:

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5 0

3 years ago

Consider the rate law below.

Serga [27]

C. quadruples the rate

<h3>Further explanation</h3>

Given

The rate law :

R=k[A]²

Required

The rate

Solution

There are several factors that influence reaction kinetics :

1. Concentration
2. Surface area
3. Temperature
4. Catalyst
5. Pressure
6. Stirring

The rate is proportional to the concentration.

If the concentration increased, the reaction rate will increase

The reaction is second-order overall(The exponent is 2)

The concentration of A is doubled, the reaction rate will increase :

r = k[A]² ⇒ r= k[2A]²⇒r=4k[A]²

<em>The reaction rate will quadruple.</em>

5 0

3 years ago

In a chemical interaction 10 g of hydrogen chloride is added to 20 g of zinc to form 24 g of zinc chloride and a certain amount

dybincka [34]

6g of hydrogen gas is my answer. I'm sorry if I'm wrong.

7 0

3 years ago

Read 2 more answers

A sample of oxalic acid (a diprotic acid of the formula H2C2O4) is dissolved in enough water to make 1.00 L of solution. A 100.0

OleMash [197]

<u>Answer:</u> The mass of original oxalic acid sample is 6.75 grams

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2C_2O_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=?M\\V_1=100.0mL\\n_2=1\\M_2=0.750M\\V_2=20.0mL$

Putting values in above equation, we get:

$2\times M_1\times 100.0=1\times 0.750\times 20.0\\\\M_1=\frac{1\times 0.750\times 20.0}{2\times 100.0}=0.075M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

Given mass of oxalic acid = ? g

Molar mass of oxalic acid = 90 g/mol

Molarity of solution = 0.075 M

Volume of solution = 1.00 L

Putting values in above equation, we get:

$0.075M=\frac{\text{Mass of oxalic acid}}{90g/mol\times 1L}\\\\\text{Mass of oxalic acid}=(0.075\times 90\times 1)=6.75g$

Hence, the mass of original oxalic acid sample is 6.75 grams

7 0

2 years ago