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3 years ago

What is a system that performs different functions according to a fixed schedule?

Engineering

2 answers:

geniusboy [140]3 years ago

4 0

I'm pretty sure your answer is B, because Sequential Control operates during order like a schedule

Sequential Control=A control system in which the individual steps are processed in a predetermined order, progression from one sequence step to the next being dependent on defined conditions being satisfied.

Tell me if I'm incorrect but, Hope this helps!

OleMash [197]3 years ago

3 0

This is so funny jqjqjajajajajajajaja

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In order to be a Mechanical Engineer, you need to:

djyliett [7]

Answer:

Explanation:

it is compulsory to have a bachelor's degree

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3 years ago

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DedPeter [7]

Answer:

yes.

Explanation:

5 0

3 years ago

A particle travels along a straight line with a velocity v = (12 – 3t2) m/s. When t = 1 s, the particle is located 10 m to the l

arlik [135]

Answer:

The displacement from t = 0 to t = 10 s, is -880 m

Distance is 912 m

Explanation:

$v = (12 - 3t^2) m/s = ds/dt$ . . . . . . . . . . A

integrate above equation we get

$s = 12t - t^3 + C$

from information given in the question we have

t = 1 s, s = -10 m

so distance s will be

-10 = 12 - 1 + C,

C = -21

$s(t) = 12t - t^3 - 21$

we know that acceleration is given as

$a(t) = dv/dt = -6t$

[FROM EQUATION A]

Acceleration at t = 4 s, a(4) = -24 m/s^2

for the displacement from t = 0 to t = 10 s,

$s(10) - s(0) = (12*10 - 10^3 - 21) - (-21) = -880 m$

the distance the particle travels during this time period:

let v = 0,

$3t^2 = 12$

t = 2 s

Distance $= [s(2) - s(0)] + [s(2) - s(10)] = [1\times 2 - 2^3] + [(12\times 2 - 2^3) - (12\times 10 - 10^3)] = 912 m$

7 0

4 years ago

The diffusion coefficients for iron in nickel are given at two temperatures:T (K)D (m2/s)12739.4 × 10–1614732.4 × 10–14(a) Deter

hram777 [196]

Answer:

The diffusion coefficients for iron in nickel are given at two temperatures:

T (K) 1273 1473

D ( $m^{2}$ /s) 9.4 × $10^{-16}$ 2.4 × $10^{-14}$

(a) Determine the values of Do and the activation energy Qd.

(b) What is the magnitude of D at 1100°C (1373 K)?

A

The pre-exponential factor Do = 2.1 x $10^{-16}$

The activation energy Qd = 252,609 J/mol

B

The diffusion coefficient D= 5.14 x $10^{-15}$

Explanation:

The full explanation is contained in the attached images;

5 0

4 years ago

A household refrigerator that has a power input of 450 W and a COP of 1.5 is to cool five large watermelons, 10 kg each, to 8°C.

Andreyy89

Answer:

6222.22 sec

Explanation:

Given data the power input to the refrigerator is 450 W

The COP of refrigerator is 1.5

Temperature $T_1=8^{\circ}C$

$T_2=28^{\circ}C$

mass of watermelon =10 kg

specific heat =4.2 KJ/kg°C

The amount of heat removed from 5 watermelon

$Q=mc_pdt=5\times 10\times 4.2\times (28-8)=4200 KJ$

We know that $COP=\frac{Q_1}{W}$

$1.5=\frac{Q_1}{450}$

$Q_1=675$ W=0.675 KW

so time required to cool the watermelon is

$t=\frac{Q_1}{Q_2}=\frac{4200}{0.675}=6222.22 sec$

4 0

3 years ago