Answer:
a.) -147V
b.) -120V
c.) 51V
Explanation:
a.) Equation for potential difference is the integral of the electrical field from a to b for the voltage V_ba = V(b)-V(a).
b.) The problem becomes easier to solve if you draw out the circuit. Since potential at Q is 0, then Q is at ground. So voltage across V_MQ is the same as potential at V_M.
c.) Same process as part b. Draw out the circuit and you'll see that the potential a point V_N is the same as the voltage across V_NP added with the 2V from the other box.
Honestly, these things take practice to get used to. It's really hard to explain this.
Answer:
la escuela,en casa y listo...............
Technical Drawings give a better understanding of what is needed and required in the project.
Explanation:
Answer:
<em><u>THE ANSWER IS: B</u></em>
Explanation:
I took the Unit test and the answer is B
Answer:
connecting two independent clauses