Using the quadratic formula, we have:
, so our solutions are
and
.
Answer:
(x^2 + x -1) x (x^2+3x-3)
Step-by-step explanation:
-6x-5+x^4+4x^3-x^2+8
-6x+3+x^4+4x^3-x^2
-6x+3+x^4+x^3+3x^3-x^2
-3x-3x+3+x^2 x(x^2+x-1)+3x^3 +3x^2-3x^2
3x *(x^2+x+x-2)-3(x^2+x-1)+x^2 *(x^2+x-1)
= (x^2+x-1) x (x^2+3x-3)
* means multiply btw
You might have made an error the first time you solved for x. I got x = -0.5.
When you have your log base 4, the way you cancel that out is by making 4 the base on both sides, so you get 4^(log4) to reduce to 1, and you're left with:
2x + 3 = 4^(1/2) ... Simplify
2x + 3 = 2
2x = -1
x = -1/2
If you plug that back in, everything checks out. Maybe double check your use of logarithm/exponent properties?
c
Answer:
Step-by-step explanation:
Answer:
2 units. Hope this helps!