The coefficient of friction is 0.363
Explanation:
There are two forces acting on the scooter in the horizontal direction:
- The applied force, F = 1850 N, forward
- The frictional force, , backward
Since the scooter is moving at constant speed, the acceleration is zero, so the net force acting on the scooter must be zero. Therefore we can write:
The frictional force can be written as
(1)
where
is the coefficient of friction
R is the normal reaction of the ground on the scooter
For a flat horizontal surface, there is equilibrium along the vertical direction, so the normal reaction is equal to the weight:
where
m = 520 kg is the mass
is the acceleration of gravity
Substituting into (1),
and solving for ,
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