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mojhsa [17]
3 years ago
10

How do sex cells differ from other human cells?

Physics
1 answer:
VLD [36.1K]3 years ago
7 0
Sex cells have half as many chromosomes as other cells. Sex cells are therefore called haploid.
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One end of an insulated metal rod is maintained at 100 ∘C and the other end is maintained at 0.00 ∘C by an ice–water mixture. Th
lozanna [386]

Answer:

k=105.0359\times 10^4\,W.m^{-1}.K^{-1}

Explanation:

Given:

temperature at the hotter end, T_H=100^{\circ}C

temperature at the cooler end, T_C=0^{\circ}C

length of rod through which the heat travels, dx=0.7\,m

cross-sectional area of rod, A=1.1\times 10^{-4}\,cm^2

mass of ice melted at zero degree Celsius, m=8.7\times 10^{-3}\,kg

time taken for the melting of ice, t=15\times60=900\,s

thermal conductivity k=?

By Fourier's Law of conduction we have:

\dot{Q}=k.A.\frac{dT}{dx}......................................(1)

where:

\dot{Q}=rate of heat transfer

dT= temperature difference across the length dx

Now, we need the total heat transfer according to the condition:

we know the latent heat of fusion of ice,  L = 334000\,J.kg^{-1}

Q=m.L

Q=8.7\times 10^{-3}\times 334000

Q=2905.8\,J

Now the heat rate:

\dot{Q}=\frac{Q}{t}

\dot{Q}=\frac{2905.8}{900}

\dot{Q}=3.2287\,W

Now using eq,(1)

3.2287=k\times 1.1\times 10^{-4} \times \frac{100}{0.7}

k=205.4606\,W.m^{-1}.K^{-1}

8 0
3 years ago
A 0.45-kilogram football traveling at a speed of 22 meters per second is caught by an 84-kilogram stationary receiver. if the fo
Troyanec [42]

Impulse = Change in momentum.  
The ball was moving with a momentum of 0.45 * 22 = 9.9  
The ball comes to rest in the receivers arm; this means the ball's final velocity = 0. So mv2 = 0.45 * 0  
The magnitude of the impact is just the change in momentum. 9.9 - (0.45 * 0) = 9.9
3 0
3 years ago
Một chất điểm DĐĐH có phương trình x=Acos(omega t). Tìm thời gian chất điểm qua vtcb theo chiều dương lần thứ 2?
Arada [10]

Answer:

yyeyrhdhshysyeuhdjxnxmzmakalwooeitjtjdjjs

8 0
3 years ago
[ b) The time of reverberation of an empty hall without and with 500 audiences is 1.5 sec and 1.4 sec respectively. Find the rev
Lilit [14]

The reverberation time with 800 audiences is 0.875 seconds.

<h3>Reverberation time with 800 audience</h3>

R₁V₁ = R₂V₂

where;

  • R₁ is the reverberation time with 400 audience
  • R₂ is the reverberation time with 800 audience
  • V₁ is initial volume
  • V₂ is final volume

R₂ = R₁V₁/V₂

R₂ = (1.4 x 500) / 800

R₂ = 0.875 seconds

Thus, the reverberation time with 800 audiences is 0.875 seconds.

Learn more about reverberation time here: brainly.com/question/9278479

#SPJ1

4 0
1 year ago
Students in an introductory physics lab are performing an experiment with a parallel-plate capacitor made of two circular alumin
Alex777 [14]

Answer:

0.92 μC

Explanation:

In a parallel-plate capacitor, the electric field formed is equal to the charge density divited by the vacuum permisivity e0, as there are no dielectric between the plates. e0 is equal to 8.85*10^-12 C^2/Nm^2. The charge density is the total charge of each individual plate divided by its area. Then, the maximum charge allowed will be equal to:

E = \frac{o}{e_0} = \frac{Q}{Ae_0} \\ Q = E*A*e_0 = 3*10^6 N/C * (0.25*\pi *(0.21m)^2)*8.85*10^{-12}C^2/Nm^2 = 9.196 *10^{-7} C

or 0.92 μC

7 0
2 years ago
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