M=n/V , 4.5=n/1.5 , (45/10). (15/10)=n , (9/2).(3/2)=n=27/4 , n=6,75
As a trend or pattern, the atomic radius decreases as you go left to right across the period, but increases as you go down a particular group.
Answer: alright now listen fe203(s)=567.66666
Explanation:
First, we write the balanced equation for this reaction:
2KI + Pb(NO₃)₂ → 2KNO₃ + PbI₂
From this equation, we see that there are 2 moles of potassium iodide required for each mole of lead (II) nitrate. Moreover, we may use the formula:
Moles = volume (in L) * molarity
We find the molar relation ship for KI : Pb(NO₃)₂ to be 2 : 1. So:
M₁V₁ = 2M₂V₂
V₁ = 2M₂V₂/M₁
V₁ = 2 * 0.112 * 0.155 / 0.2
V₁ = 0.1736 L
The volume required is 173.6 mL
Because subatomic particles ARE what make up atoms.