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meriva
3 years ago
15

In a common experiment in the general chemistry laboratory, magnesium metal is heated in air to produce MgO. MgO is a white soli

d, but in these experiments it often looks gray, due to small amounts of Mg3N2 , a compound formed as some of the magnesium reacts with nitrogen. Write a balanced equation for each reaction.
Chemistry
1 answer:
Digiron [165]3 years ago
6 0

Explanation:

When magnesium metal burns is heated i the air it forms magnesium oxide.The balanced chemical reaction is given as:

2Mg+O_2\rightarrow 2MgO

2 moles of magnesium metal when reacts with 1 moles of oxygen it gives 2 moles of magnesium oxide which is white in color.

Some times along with formation of magnesium oxide small amount of magnesium nitride also produced due to which magnesium oxide appears grey in color .The balanced chemical reaction is given as:

3Mg+N_2\rightarrow Mg_3N_2

3 moles of magnesium combines with 1 mol of nitrogen gas to to give 1 mol of magnesium nitride.

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Equal volumes of 0.2 M ammonia and 0.2 M nitric acid, HNO₃, are mixed. Write the net ionic equation for the reaction and identif
Black_prince [1.1K]

Answer:

The net ionic equation is

H₃O⁺+NH₃ ↔ NH₄⁺+H₂O

Explanation:

To write the net ionic equation, we are required to dissociate the into ions all strong acids and strong bases

Hence, nitric acid which is a strong acid is dissociated as follows

HNO₃+H₂O → H₃O⁺ + NO₃⁻

in the above equation, the nitrate ion  NO₃⁻, is a spectator ion because it is only present and does not partake in the chemical reaction so it is left out of the net ionic equation equation

Also the it is required to keep together weak bases in the solution therefore  for NH₃ which is a weak base we have

NH₃ + H₃O⁺ → NH₄⁺ + H₂O

Hence, the net ionic equation becomes

H₃O⁺ (aq) + NH₃ ↔ NH₄⁺(aq) + H₂O (l)

3 0
4 years ago
4g of sugar is dissolved in 46 g of water calculate the concentration as percent by mass
Lina20 [59]
The  concentration as  %  by  mass  is  calculated as below

mass  of  solute/mass of  solvent x100
mass of  solute(sugar) = 4g
mass of   solvent(water) =46  g

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3 0
3 years ago
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Which mass of urea CO(NH2)2 contain the same mass of nitrogen as 101.1g of potassium nitrate?
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M(KNO₃)=101.1 g/mol
M(CO(NH₂)₂)=60.1 g/mol

m(N)=M(N)m(KNO₃)/M(KNO₃)

m(N)=2M(N)m(CO(NH₂)₂)/M(CO(NH₂)₂)

2m(CO(NH₂)₂)/M(CO(NH₂)₂)=m(KNO₃)/M(KNO₃)

m(CO(NH₂)₂)=M(CO(NH₂)₂)m(KNO₃)/(2M(KNO₃))

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Answer:

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