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meriva
3 years ago
15

In a common experiment in the general chemistry laboratory, magnesium metal is heated in air to produce MgO. MgO is a white soli

d, but in these experiments it often looks gray, due to small amounts of Mg3N2 , a compound formed as some of the magnesium reacts with nitrogen. Write a balanced equation for each reaction.
Chemistry
1 answer:
Digiron [165]3 years ago
6 0

Explanation:

When magnesium metal burns is heated i the air it forms magnesium oxide.The balanced chemical reaction is given as:

2Mg+O_2\rightarrow 2MgO

2 moles of magnesium metal when reacts with 1 moles of oxygen it gives 2 moles of magnesium oxide which is white in color.

Some times along with formation of magnesium oxide small amount of magnesium nitride also produced due to which magnesium oxide appears grey in color .The balanced chemical reaction is given as:

3Mg+N_2\rightarrow Mg_3N_2

3 moles of magnesium combines with 1 mol of nitrogen gas to to give 1 mol of magnesium nitride.

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6.7

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4 0
3 years ago
What can be categorized as a use of plasma in technology
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3 0
3 years ago
What is the mass of KOH found in a 785 mL of a 1.43 M solution of KOH
My name is Ann [436]

Molarity is defined as the ratio of number of moles to the volume of solution in litres.

The mathematical expression is given as:

Molarity = \frac{Number of moles}{volume of solution in litres}

Here, molarity is equal to 1.43 M and volume is equal to 785 mL.

Convert mL into L

As, 1 mL = 0.001 L

Thus, volume = 785\times 0.001 = 0.785 L

Rearrange the formula of molarity in terms of number of moles:

Number of moles =molarity\times volume of solution in litres

n = 1.43 M \times 0.785 L

= 1.12255 mole

Now,  Number of moles  = \frac{mass in g}{molar mass}

Molar mass of potassium hydroxide  = 56.10 g/mol

1.12255 mole  = \frac{mass in g}{56.10 g/mol}

mass in g = 1.12255 mole\times 56.10 g/mol

= 62.97 g

Hence, mass of KOH = 62.97 g



7 0
3 years ago
What is the manganese (IV) oxide function
viva [34]

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It is used as a catalyst.

6 0
3 years ago
Assuming 1 mol of Fe3+ and 2 mol of SCN- were allowed to react and reach equilibrium. 0.5 mol of product was formed. The total v
zaharov [31]

Answer:

a. 0.5 mol

b. 1.5 mol

c. 0.67

Explanation:

Fe3+ + SCN- -----> [FeSCN]2+

a. The ratio of the product to Fe3+ is 1:1. Meaning that if 0.5 mol of product was produced up then 0.5 mol of Fe3+ was used. Leaving 0.5 mol remaining at equilibrium

b. The ratio of the product to SCN= is 1:1. Meaning that if 0.5 mol of product was produced up then 0.5 mol of SCN- was used. Leaving 1.5 mol remaining at equilibrium

c. KC =  0.5/(0.5*1.5) =  0.67

3 0
3 years ago
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