Let n be the sum of all 6 numbers:
In the 1st case n/6 = 41 ==> n =246
in the 2nd case n'/5 = 46===> n' =230, the unknown number is n-n' =246-230
= 16
the discount is 22.5 * .2 =
round 22.5 to 20
20 *.2
Choice B
(a) since we are given that f(8) = 9, the inverse of 9 is simply 8. Therefore, f^-1(9) = 8.
(b) Again, f is the inverse of f^-1, therefore, you simply switch numbers, and you get that f(-3) = -7.
Answer:
g(x) = (x + 2)^2 + 1
Step-by-step explanation:
From the graph/image that you have provided said translated shift of
f(x) -> g(x)
f(x) = x^2 , g(x) = a(x -h)^2 +k
h is shift right/left
k is shift up/down.
It appears that the shift is left 2 and up 1.
h = -2 and k = 1
g(x) = (x - (-2))^2 +1
g(x) = (x + 2)^2 + 1
