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MakcuM [25]
2 years ago
11

I will give 100 points to anyone who friends me

Chemistry
2 answers:
Annette [7]2 years ago
7 0

Answer:

i doubt that but i'll friend you anyways.. haha

Explanation:

Thanks for the points

kolbaska11 [484]2 years ago
5 0

Answer:

I'm answering this for points

Explanation:

:)

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if kept at a constant temperature, what is the concentration at 865s if the initial concentration was 0.0225M
Anestetic [448]

Answer:

[SO_2Cl_2]=0.0175M

Explanation:

Hello!

In this case, considering that the decomposition reaction of SO2Cl2 is first-order, we can write the rate law shown below:

r=-k[SO_2Cl_2]

We also consider that the integrated rate law has been already reported as:

[SO_2Cl_2]=[SO_2Cl_2]_0exp(-kt)

Thus, by plugging in the initial concentration, rate constant and elapsed time we obtain:

[SO_2Cl_2]=0.0225Mexp(-2.90x10^{-4}s^{-1}*865s)

[SO_2Cl_2]=0.0175M

Best regards!

8 0
3 years ago
Contour plowing, conservation plowing and crop rotation are ways to __________ soil. a. prevent c. lose b. conserve d. none of t
morpeh [17]

Explanation:

prevent becoz crop rotation means using it by planting the crop according to nuetrients so ur soil is prevented

8 0
3 years ago
Read 2 more answers
Who discovered phosphate?
iris [78.8K]

Answer:

Hennig Brand

Explanation:

4 0
3 years ago
All scientific ___________ must be based on careful and rational examinations of the facts.
ipn [44]
I think you forgot to give the options along with the question. I am answering the question based on my knowledge and research.All scientific theories <span>must be based on careful and rational examinations of the facts. I hope that this is the answer that you were looking for and it has actually come to your help.</span>
8 0
4 years ago
Read 2 more answers
One reaction involved in the conversion of iron ore to the metal is FeO(s) + CO(g) → Fe(s) + CO2(g) Use Hess’s Law to calculate
Ugo [173]

Answer:

\delta H_{rxn} = -66.0  \ kJ/mole

Explanation:

Given that:

3FeO_3_{(s)}+CO_{(g)} \to 2Fe_3O_4_{(s)} +CO_{2(g)} \  \ \delta H = -47.0 \ kJ/mole  -- equation (1)  \\ \\ \\ Fe_2O_3_{(s)} +3CO_{(g)} \to 2FE_{(s)} + 3CO_{2(g)}  \ \ \delta H = -25.0 \ kJ/mole  -- equation (2)  \\ \\ \\ Fe_3O_4_{(s)} + CO_{(g)} \to 3FeO_{(s)} + CO_{2(g)} \ \delta H = 19.0 \ kJ/mole  -- equation (3)

From equation (3) , multiplying (-1) with equation (3) and interchanging reactant with the product side; we have:

3FeO_{(s)} + CO_{2(g)}    \to    Fe_3O_4_{(s)} + CO_{(g)}   \ \delta H = -19.0 \ kJ/mole  -- equation (4)

Multiplying  (2) with equation (4) ; we have:

6FeO_{(s)} + 2CO_{2(g)}    \to    2Fe_3O_4_{(s)} + 2CO_{(g)}   \ \delta H = -38.0 \ kJ/mole  -- equation (5)

From equation (1) ; multiplying (-1) with equation (1); we have:

2Fe_3O_4_{(s)} +CO_{2(g)} \to     3FeO_3_{(s)}+CO_{(g)}   \  \ \delta H = 47.0 \ kJ/mole  -- equation (6)

From equation (2); multiplying (3) with equation (2); we have:

3 Fe_2O_3_{(s)} +9CO_{(g)} \to 6FE_{(s)} + 9CO_{2(g)}  \ \ \delta H = -75.0 \ kJ/mole  -- equation (7)

Now; Adding up equation (5), (6) & (7) ; we get:

6FeO_{(s)} + 2CO_{2(g)}    \to    2Fe_3O_4_{(s)} + 2CO_{(g)}   \ \delta H = -38.0 \ kJ/mole  -- equation (5)

2Fe_3O_4_{(s)} +CO_{2(g)} \to     3FeO_3_{(s)}+CO_{(g)}   \  \ \delta H = 47.0 \ kJ/mole  -- equation (6)

3 Fe_2O_3_{(s)} +9CO_{(g)} \to 6FE_{(s)} + 9CO_{2(g)}  \ \ \delta H = -75.0 \ kJ/mole  -- equation (7)

<u>                                                                                                                      </u>

FeO  \ \ \ +  \ \ \ CO   \ \  \to   \ \ \ \ Fe_{(s)} + \ \ CO_{2(g)} \ \ \  \delta H = - 66.0 \ kJ/mole

<u>                                                                                                                     </u>

<u />

\delta H_{rxn} = \delta H_1 +  \delta H_2 +  \delta H_3    (According to Hess Law)

\delta H_{rxn} = (-38.0 +  47.0 + (-75.0)) \ kJ/mole

\delta H_{rxn} = -66.0  \ kJ/mole

8 0
3 years ago
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