I believe if it were heavier with more mass, then the sun would pull it in and there would be no mercury. It might also be hotter.
It is B because the other ones are good.
Answer:
P= 454.11 N
Explanation:
Since P is the only horizontal force acting on the system, it can be defined as the product of the acceleration by the total mass of the system (both cubes).

The friction force between both cubes (F) is defined as the normal force acting on the smaller cube multiplied by the coefficient of static friction. Since both cubes are subject to the same acceleration:

In order for the small cube to not slide down, the friction force must equal the weight of the small cube:

The smallest magnitude that P can have in order to keep the small cube from sliding downward is 454.11 N
This would be true. On Jupiter you would weigh 234 pounds if you were 100 pounds on Earth.