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polet [3.4K]
3 years ago
5

A researcher wants to experiment with an element that reacts like phosphorus (P) but has a greater atomic mass. Which element sh

ould the researcher select for the experiment?
1.)Nitrogen (N)
2.)Silicon (Si)
3.)Arsenic (As)
4.)Sulfur (S)
Chemistry
2 answers:
IgorC [24]3 years ago
4 0

Answer:

Most likely N or S it might not be safe but that is what experiments do I guess.

Explanation:

wel3 years ago
3 0

Answer:

the answer correct is 4.

sulfur(s)

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Why is performing extraction with several small portions of a solvent more officient than a single extraction with the same tota
elena55 [62]

With various extractions the amount of material left in the trash will be lower, ergo the extraction will be more perfect. Various extractions with fewer amounts of solvent are more efficient than a single extraction with a huge amount of solvent.

<u>Explanation:</u>

Surely multiple extractions are better than the single large extraction. Because extraction is about maximizing outside field communication between the two solvents, and you easily get more surface area contact with fewer amounts.

You can merge two smaller portions quicker and more completely than with large portions.

6 0
3 years ago
The electronegativity of nitrogen (N) is 3.0, while the electronegativity of hydrogen (H) is 2.1. Knowing this, consider how the
Ede4ka [16]

Answer:

NH3 is polar due to the bonds between nitrogen and hydrogen which have different electronegativity and due also to its asymmetrical shape.

Explanation:

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4 0
3 years ago
What is the bond length of cubic close packing?
Oxana [17]

Answer:

1.5a

Explanation:

4 0
3 years ago
A chemist must prepare 300.0mL of nitric acid solution with a pH of 0.70 at 25°C. He will do this in three steps: Fill a 300.0mL
d1i1m1o1n [39]

<u>Answer:</u> The volume of concentrated solution required is 9.95 mL

<u>Explanation:</u>

To calculate the pH of the solution, we use the equation:

pH=-\log[H^+]

We are given:

pH = 0.70

Putting values in above equation, we get:

0.70=-\log[H^+]

[H^+]=10^{-0.70}=0.199M

1 mole of nitric acid produces 1 mole of hydrogen ions and 1 mole of nitrate ions.

Molarity of nitric acid = 0.199 M

To calculate the volume of the concentrated solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated nitric acid solution

M_2\text{ and }V_2 are the molarity and volume of diluted nitric acid solution

We are given:

M_1=7.0M\\V_1=?mL\\M_2=0.199M\\V_2=350mL

Putting values in above equation, we get:

7.0\times V_1=0.199\times 350.0\\\\V_1=\frac{0.199\times 350}{7.0}=9.95mL

Hence, the volume of concentrated solution required is 9.95 mL

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2 years ago
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